Why is the x-component of the electric field at point P positive?

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SUMMARY

The x-component of the electric field at point P is confirmed to be positive based on the equation E(P)=(k*Q)/(3î )−(k*Q*ĵ)/2. While the magnitudes of the components are accurate, the signs require clarification. The positive sign of the x-component arises from the direction of the electric field vector relative to the charge Q. Understanding vector components in electric fields is crucial for accurate calculations.

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Homework Statement
Three charges q1,q2 and q3 are placed on the vertices of an isosceles triangle ABC
respectively. As shown in the picture. Determine the electric field E
at point P and the electric potential difference
Relevant Equations
E=k*q*hatr/|r|^2
I got the answer:
E(P)=(k*Q)/(3î )−(k*Q*ĵ) /2
Can someone confirm if this is the right answer?
 
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The magnitudes of the components are correct but not the signs. Can you see why the x-component should be positive? The y-component is fine.
 

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