Why Might Ay Be Bigger Than Ax in a Triangle?

  • Thread starter Thread starter Make
  • Start date Start date
AI Thread Summary
In the discussion, the main question revolves around why Ay can be greater than Ax in a triangle, despite the given dimensions of 4 for the X side and 3 for the Y side. The user expresses confusion about the equation for the x dimension, questioning the validity of using A as a normal force. It is clarified that A must balance the other forces, which are primarily vertical, indicating that A's direction is closer to vertical than horizontal. This understanding helps explain the relationship between Ay and Ax in the context of the triangle. The discussion emphasizes the importance of force direction in analyzing the problem.
Make
Messages
20
Reaction score
0

Homework Statement





The attached question(question 1) is in finnish, but you'll understand it no problem!;) The answers are given at the end of the text part of the question.

Homework Equations





The Attempt at a Solution


Firstly, I'm wondering how can Ay be bigger than Ax even though the X side of the little triangle at the left end of the boom is 4 and Y is 3?

Secondly, why can't I write the equation for the x dimension as follows: \sumF= -400sin15+0,8A=0

 

Attachments

Physics news on Phys.org
A is not a normal*** force. If it were, we'd have

Ax = 3/5 A​

A must act to balance the other forces that are present. Since the other forces are close to being vertical, A is closer to vertical than to horizontal.


*** "normal" means the force is perpendicular to the surface
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »

Similar threads

Orbital dynamics math review for a computer simulation
Replies
11
Views
1K
EMF in bigger loops kept on both sides of a small loop
Replies
2
Views
2K
Electric field in a capacitor with a dielectric
Replies
5
Views
2K
Find the Force to move 2 objects, and force between the 2
Replies
5
Views
2K
Depth of a basketball floating on water
Replies
9
Views
883
Finding the center of mass of an arbitrary uniform triangle
Replies
20
Views
7K
Solving Semi-circle Inside Triangle Geometry Problem
Replies
13
Views
3K
Problem 10.30 (with Hints) - Mastering Physics - Rotational Inertia
Replies
2
Views
6K
What is the speed of three stars rotating in an equilateral triangle?
Replies
5
Views
2K
Force Applied to Two Blocks: Which is Bigger?
Replies
9
Views
2K

Hot Threads

Recent Insights

Back
Top