Why period is half ? Spring problem

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AI Thread Summary
The discussion centers on a mass sliding on a frictionless surface that strikes a spring, raising questions about the period of oscillation and the duration of contact with the spring. The period of oscillation is derived from the spring constant and mass, leading to the conclusion that the mass is in contact with the spring for half of the oscillation period. This is because a full cycle involves the mass moving through maximum compression and returning to its original position, while contact occurs only during the compression phase. The key takeaway is that the mass loses contact with the spring when the spring force reaches zero, indicating it only engages with the spring for half the period. Understanding these dynamics clarifies why the period is effectively halved in this scenario.
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Homework Statement


A mass m slides along a frictionless horizontal surface at speed v initial. It strikes a spring of constant k attached to a rigid wall. After a completely elastic encounter with the spring, the mass heads back in the direction it came from.

(a)In terms of k, m, and v initial, determine how long the mass is in contact with the spring.

(b)In terms of k, m, and v initial, determine the maximum compression of the spring.


Homework Equations



The one thing i don't know is why period = 1/2 ??


The Attempt at a Solution



I know horizontal force will be only the force exert by spring.
I know the algebra below:
f= 1/2π * √(k/m)

Period = P = 1/f ergo
t = P/2
= 1/2* 1/f
= 1/2 * 2π √(m/k)
= π √(m/k)
 
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k31453 said:
The one thing i don't know is why period = 1/2 ??

Think about the difference between this scenario and the "usual" spring oscillator where the mass is fixed to the end of the spring. What constitutes a full cycle of the oscillation?
 
I think you mean that the mass will be in contact with the spring for half the period of oscillation (if the mass was attached to the spring).
 
Yes BASIC But how ?

And I know when max displacement the T is going to be 1.
 
k31453 said:
Yes BASIC But how ?

And I know when max displacement the T is going to be 1.

You should listen to what gneill said. Suppose you started at zero compression or stretch (as is the case here) and max inward speed. If the mass had been attached, what would *happen* during a full period of oscillation?

How much of that happens here? Hint: the mass loses contact with the spring when the spring force goes to zero.
 
half period

Assume the mass is attached to the spring - a necessary condition for SHM to occur.
At position 1 the spring is relaxed.
At position 2 the mass is at its rightmost extreme position and the spring is at max compression.
At position 3 the spring is back to its relaxed state.
At position 4 the mass is at its leftmost extreme position and the spring is at max extension.
At position 5 the spring is again relaxed.
 

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