Why period is half ? Spring problem

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Homework Help Overview

The problem involves a mass sliding on a frictionless surface that strikes a spring, leading to questions about the duration of contact with the spring and the maximum compression. It relates to concepts in mechanics, specifically oscillatory motion and spring dynamics.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the period of oscillation and the contact time with the spring, questioning why the contact time is considered to be half the period. They explore the implications of the mass being attached to the spring versus being free.

Discussion Status

Participants are actively engaging with the concepts, with some suggesting that the mass is in contact with the spring for half the period of oscillation. The discussion is focused on clarifying the conditions under which this occurs and the differences from typical spring oscillators.

Contextual Notes

There is a mention of the mass losing contact with the spring when the spring force reaches zero, which is a critical point in understanding the dynamics of the system. The discussion also references the need to consider the full cycle of oscillation in the context of the problem.

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Homework Statement


A mass m slides along a frictionless horizontal surface at speed v initial. It strikes a spring of constant k attached to a rigid wall. After a completely elastic encounter with the spring, the mass heads back in the direction it came from.

(a)In terms of k, m, and v initial, determine how long the mass is in contact with the spring.

(b)In terms of k, m, and v initial, determine the maximum compression of the spring.


Homework Equations



The one thing i don't know is why period = 1/2 ??


The Attempt at a Solution



I know horizontal force will be only the force exert by spring.
I know the algebra below:
f= 1/2π * √(k/m)

Period = P = 1/f ergo
t = P/2
= 1/2* 1/f
= 1/2 * 2π √(m/k)
= π √(m/k)
 
Last edited:
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k31453 said:
The one thing i don't know is why period = 1/2 ??

Think about the difference between this scenario and the "usual" spring oscillator where the mass is fixed to the end of the spring. What constitutes a full cycle of the oscillation?
 
I think you mean that the mass will be in contact with the spring for half the period of oscillation (if the mass was attached to the spring).
 
Yes BASIC But how ?

And I know when max displacement the T is going to be 1.
 
k31453 said:
Yes BASIC But how ?

And I know when max displacement the T is going to be 1.

You should listen to what gneill said. Suppose you started at zero compression or stretch (as is the case here) and max inward speed. If the mass had been attached, what would *happen* during a full period of oscillation?

How much of that happens here? Hint: the mass loses contact with the spring when the spring force goes to zero.
 
half period

Assume the mass is attached to the spring - a necessary condition for SHM to occur.
At position 1 the spring is relaxed.
At position 2 the mass is at its rightmost extreme position and the spring is at max compression.
At position 3 the spring is back to its relaxed state.
At position 4 the mass is at its leftmost extreme position and the spring is at max extension.
At position 5 the spring is again relaxed.
 

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