Why specific latent heat of vaporisation > fusion?

AI Thread Summary
The discussion focuses on understanding why the specific latent heat of vaporization is greater than that of fusion. It highlights that during evaporation, the change in volume is significantly larger than during melting, leading to a greater increase in potential energy and internal energy. The equation ΔU = mL + pΔV is referenced, emphasizing the importance of correctly interpreting the work done on the system, which should be negative due to work being done by the system. The clarification of the sign problem is crucial to grasping the concept. Overall, the key takeaway is that the larger volume change during vaporization accounts for its higher latent heat compared to fusion.
Janiceleong26
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1. Homework Statement
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Homework Equations


First law of thermodynamics, ΔU=q+W

The Attempt at a Solution


Ok so, I know that when liquid evaporates, the change in volume is much greater than that when solid melts. And for both cases, distance of separation of atoms increases too, so PE increases, and hence, internal energy increases.
So, ΔU=mL+ pΔV
L=(ΔU-pΔV) /m
But how do we know that the term (ΔU-pΔV) is greater for vaporisation than that of fusion?
 
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Janiceleong26 said:

Ok so, I know that when liquid evaporates, the change in volume is much greater than that when solid melts.
Well, that is in fact the main essence of the answer.

Janiceleong26 said:
So, ΔU=mL+ pΔV
There is a sign problem here. The work done on the system ##W## should be ## - p \Delta V## - do you see why?
 
Fightfish said:
Well, that is in fact the main essence of the answer.There is a sign problem here. The work done on the system ##W## should be ## - p \Delta V## - do you see why?
Ahh I see why now. Yup, because it's work done by system.
Thanks !
 
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