Engineering Window Detector Circuit Design: LED Activation for Voltage Thresholds

AI Thread Summary
The discussion centers on designing a window detector circuit to activate an LED when voltage thresholds are crossed, specifically above 2V or below 1V. The user seeks clarification on resistor values, noting that R2 consistently calculates to 1/2, which seems impractical compared to typical resistor values used. Concerns are raised about potential conflicts between comparators driving the output high or low, and the need for a solution to prevent oscillation. Suggestions include using open collector comparators and implementing hysteresis to stabilize the circuit near the threshold voltages. The conversation emphasizes the importance of proper resistor selection and circuit stability in comparator designs.
dylandrop
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Homework Statement



I think I know how to do this but wanted to make sure before I actually make the circuit.

Here's a general diagram:
[PLAIN]http://forum.allaboutcircuits.com/image_cache/httphome.cogeco.ca~rpaisley4ComparatorWindow.GIF

So as you can see I'm trying to make a window detector circuit that makes an LED turn on if the voltage is below or above a certain threshold. In this case, I want the LED to turn on above 2V or below 1V.


Homework Equations




I think I know how to devise the relevant equations:

VREF1 = R3 / (R1 + R2 + R3) * V+
VREF2 = (R2 + R3) / (R1 + R2 + R3) * V+


The Attempt at a Solution



I'm just unclear on what to make R values. It seems that R2 always comes out as 1/2, which makes sense mathematically (if you set VREF1 = 2, VREF2 = 1) but makes no sense to me in the real world. I've always used resistors with usually at least 100 Ohm values. But maybe I'm wrong. Help?
 
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What will be the output voltage when one of the comparators wants to drive it high while the other wants to drive it low? Which one wins? How can you prevent the fight?
 
dylandrop said:

Homework Statement



I think I know how to do this but wanted to make sure before I actually make the circuit.

Here's a general diagram:
[PLAIN]http://forum.allaboutcircuits.com/image_cache/httphome.cogeco.ca~rpaisley4ComparatorWindow.GIF

So as you can see I'm trying to make a window detector circuit that makes an LED turn on if the voltage is below or above a certain threshold. In this case, I want the LED to turn on above 2V or below 1V.


Homework Equations




I think I know how to devise the relevant equations:

VREF1 = R3 / (R1 + R2 + R3) * V+
VREF2 = (R2 + R3) / (R1 + R2 + R3) * V+


The Attempt at a Solution



I'm just unclear on what to make R values. It seems that R2 always comes out as 1/2, which makes sense mathematically (if you set VREF1 = 2, VREF2 = 1) but makes no sense to me in the real world. I've always used resistors with usually at least 100 Ohm values. But maybe I'm wrong. Help?

gneill said:
What will be the output voltage when one of the comparators wants to drive it high while the other wants to drive it low? Which one wins? How can you prevent the fight?

He's probably using open collector comparators. That would be the traditional way to do it.

@dylandrop -- I'd suggest adding hysteresis around the comparators. Comparator circuits without explicit hysteresis feedback generally oscillate/buzz near the switching points.
 
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