Work and Kinetic Energy of barrel

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SUMMARY

The discussion centers on calculating the work done against gravity when raising a 45.0 kg barrel by 6.60 m using a cable exerting 710 N. The work done against gravity is calculated using the formula W = m * g * h, resulting in 2910 J. The net work done on the barrel is determined by combining the gravitational work and the work done by the cable, emphasizing the importance of understanding the forces involved in the lifting process.

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Homework Statement


A 45.0 kg barrel is raised 6.60 m (from rest) by cable that exerts 710 N on the barrel. Neglecting any frictional energy losses, how much work is done against gravity to lift the barrel and what is the net work done on the barrel?



Homework Equations


W=m*g*h
W=F*D


The Attempt at a Solution


I am confused about the wording, "against gravity". Also when I tried to find the net work done on the barrel I did W=(45.0kg)(9.80m/s/s)(6.60m)= 2910 J. Is that right?
 
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against gravity means you are lifting the object, opposing the action of gravity.
So your W(net) = W(grav) + W(cable)

now apply W=mgh for both cases, (keeping in mind the signs), and add them to get your net work.
 

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