Work and Power- homework question

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To solve the problem, the work-energy principle can be applied, where work done (1070 J) equals the force exerted multiplied by the distance (3.05 m). The formula for force can be rearranged to F = W/d, which simplifies to F = 1070 J / 3.05 m, resulting in a force of approximately 350.82 N. The discussion emphasizes understanding the relationship between work, force, and distance in physics. Clarifying the time variable is not necessary for this specific calculation. This approach effectively determines the force exerted on the person in the cannonball act.
Eric1
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I'm doing intro-physics and I'm stuck on this Q:

"In a human cannonball act in the circus, the barrel of a cannon is 3.05 meters long and 1070 J of work are used to accelerate the person. What is the force exerted on the person (in Newtons)?"

I know the formula for force is F=ma, but i feel like I'm missing something here.
Can anyone help me?
 
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P = \frac{w}{t} = \frac{f*d}{t}

Does that help?
 
Thank you Fred.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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