Work Conceptual: Brush Up Electrical Applications & Answers

  • Thread starter Thread starter dimpledur
  • Start date Start date
  • Tags Tags
    Conceptual Work
AI Thread Summary
Understanding the concept of work in electrical applications hinges on the direction of the electric field and the movement of charges. The equation q(Vb-Va)=-W indicates that work done by the field can be positive or negative based on the charge's movement relative to the field direction. Positive work is defined when a positive charge moves against the field or a negative charge moves with it. Conversely, negative work occurs when a positive charge moves with the field or a negative charge moves against it. Clarifying these conventions is essential for accurate problem-solving in electrical applications.
dimpledur
Messages
193
Reaction score
0
I have found that I only need to brush up on my coceptual grasp of work and electrical applications. I have found that I am having negative answers when indeed the answer is positive. My question to you is, if I am following q(Vb-Va)=-W, I am assuming this is the work done by the field, and the work done by an external force (or mover) would be Wmover=-Wfield?
 
Physics news on Phys.org
dimpledur said:
I have found that I only need to brush up on my coceptual grasp of work and electrical applications. I have found that I am having negative answers when indeed the answer is positive. My question to you is, if I am following q(Vb-Va)=-W, I am assuming this is the work done by the field, and the work done by an external force (or mover) would be Wmover=-Wfield?
Whether W is positive or negative depends upon convention for field direction and what you mean by W. The convention is to have the direction of the electric field in the direction which a positive charge will naturally move. You can blame Benjamin Franklin for that.

If one defines the work required to move the charge as W, then W will be positive if the charge is positive and it moves against the direction of the electric field (ie. in the direction of increasing positive potential). If the charge is negative and the charge moves in the direction of the electric field (in the direction of decreasing positive potential which is increasingly negative potential), W also will be positive.

It is opposite (ie. W<0) if the directions of motion are reversed: If the charge is positive, then negative work is required to move the charge in the direction of the electric field (positive work is done to the charge by the field). If the charge is negative and it moves against the direction of the field, W is negative (work done on the charge).

AM
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top