Calculating Work Done by Expanding Gas in an Automobile Engine

AI Thread Summary
In an automobile engine, the gas expands from an initial volume of 50.0 cm³ and pressure of 3.00x10^6 Pa to a final volume of 300 cm³, with the final pressure calculated as 2.44x10^6 Pa. The work done by the gas during expansion is determined using the relationship PVγ = constant, which allows for integration without needing constant pressure. Participants in the discussion emphasize the importance of understanding the diatomic nature of the gas to calculate initial and final energies. The integration approach was confirmed as a valid method for solving the work done, leading to a successful resolution of the problem. Overall, the discussion highlights key thermodynamic principles in calculating work done by expanding gas in an engine.
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Homework Statement



In a cylinder of an automobile engine, immediately after combustion the gas is confined to a volume of 50.0 cm3 and has an initial pressure of 3.00x106 Pa. The piston moves outward to a final volume of 300 cm3, and the gas expands without energy transfer by heat. (a) What is the final pressure of the gas? (b) How much work is done by the gas in expanding?

Homework Equations


For this problem, assume the gas in the engine is diatomic with γ = 1.40

The Attempt at a Solution


I have already solved part (a) of this problem, which is 2.44x106 Pa, but I am having a lot of trouble with part (b). I have found the equation W = -∫VfViPdv, but don't know exactly what to do with that. I know pressure is not a constant, so it can't be brought out of the integral. I'm really not sure where I should even start with this one.
 
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Anyway you can express pressure as a function of volume?
 
Actually, can you determine the initial and final energies?
 
You know that PVγ = constant. This gives you enough information to perform the integration.

Chet
 
Chestermiller said:
You know that PVγ = constant. This gives you enough information to perform the integration.

Chet
True, but you also know that the gas is diatomic, which allows you to determine the energy at the initial state and final state. No need to integrate.
 
BiGyElLoWhAt said:
True, but you also know that the gas is diatomic, which allows you to determine the energy at the initial state and final state. No need to integrate.
Yes. I agree. You can determine the relation between the initial and final temperatures in terms of the initial and final pressures , and then use ΔU =nCvΔT.
 
Thank you both for the help. I ended up setting P = constant/Vγ and integrating from there. I appreciate it.
 
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