Work done by springs in a series

AI Thread Summary
The discussion revolves around calculating the work required to stretch two springs in series, characterized by their force constants k1 and k2. The initial attempt at a solution involves using the formula W=1/2kx^2, but the user struggles with the differing stretches of the springs due to their different constants. They propose an equation W=1/2(1/k1 + 1/k2)x^2, but later realize this approach is incorrect. The user acknowledges confusion regarding the relationship between the distances each spring stretches and seeks further assistance. The conversation highlights the complexities of applying Hooke's law to springs in series.
sillybean
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Homework Statement


Two springs, with force constants k1 and k2, are connected in series, as shown in the figure
Walker.7.68.jpg


How much work is required to stretch this system a distance x from the equilibrium position?

Homework Equations



W=1/2kx^2

The Attempt at a Solution



I have no idea how to derive this. I mean I've looked on the wikipedia article on hooke's law and figured that I just change the equation to W=1/2 (1/k1 + 1/k2)x^2

I'm guessing the problem with this is that the distances that the two stretch are not equal because of the different spring constants but I don't know how to go about showing this in an equation.
 
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is that 1/(2kx^2) or (1/2k)x^2
 
it is (1/2k)x^2
 
using 1/kt=1/k1+1/k2. Substitute into elastic potential energy equation.

Edit: forget that... Misunderstood your question I think.
 
Last edited:
i did that
W=1/2 (1/k1 + 1/k2)x^2

and this was wrong
 
sillybean said:
i did that
W=1/2 (1/k1 + 1/k2)x^2

and this was wrong

I know. That'd why I edited and said forget it, Lol.
 
ah i see. so any other takers.
 
still need help. is my theory about distances being different right?
 

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