Work under constant temperature

AI Thread Summary
An ideal monatomic gas undergoes isothermal expansion from 0.590 m³ to 1.25 m³ at a constant temperature of 780 K, with an initial pressure of 1.20x10^5 Pa. The key calculations involve determining the work done on the gas, the thermal energy transfer (Q), and the change in internal energy (ΔU). To find the final pressure, the relationship between initial and final states using the ideal gas law is essential, specifically the equation relating pressure and volume at constant temperature. The discussion emphasizes the need to calculate the final pressure to proceed with the work and energy calculations. Understanding these relationships is crucial for solving the problem effectively.
ymehuuh
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Homework Statement



An ideal monatomic gas expands isothermally from 0.590 m3 to 1.25 m3 at a constant temperature of 780 K. If the initial pressure is 1.20x10^5 Pa.
(a) Find the work done on the gas.
(b) Find the thermal energy transfer Q.
(c) Find the change in the internal energy.

Homework Equations


W= -PV
deltaU=Q-W
PfVf/PiVi = Tf/Ti


The Attempt at a Solution



I know I need to find the final pressure...but I'm not sure how to.
Do I use Pf*1.35/1.2x10^5 = 780k?
 
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ymehuuh said:

Homework Statement



An ideal monatomic gas expands isothermally from 0.590 m3 to 1.25 m3 at a constant temperature of 780 K. If the initial pressure is 1.20x10^5 Pa.
(a) Find the work done on the gas.
If T is constant and PV=nRT, what is the relationship between P1V1 and P2V2? Does that help you to find P2?

AM
 

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