Calculating Stopping Distance with Spring Forces and Friction

  • Thread starter Thread starter wxscientist
  • Start date Start date
  • Tags Tags
    Forces Spring
AI Thread Summary
To calculate the stopping distance of a block sliding on a frictionless surface that encounters a spring and friction, one must consider the forces acting on the block. The initial kinetic energy of the block is converted into spring potential energy and work done against friction. The frictional force can be calculated using the coefficient of kinetic friction and the normal force, which is equal to the weight of the block. The stopping distance is determined by the point at which the spring force equals the frictional force, leading to the block's deceleration. Ultimately, the stopping distance is equal to the maximum compression of the spring, which can be derived from the energy balance involving kinetic energy, spring potential energy, and work done against friction.
wxscientist
Messages
1
Reaction score
0
So I've been working on this for hours and trying to understand it but I just don't. It doesn't make sense to me. Here is my problem:

A block (M = 1.5 kg) is sliding along a frictionless surface with initial velocity Vo = 1.15 m/s. It comes in contact with the spring (k = 170 N/m) in the diagram, and when it does, it also experiences a friction force fk that opposed the motion. The coefficient of kinetic friction, (μk = 0.1).What is the stopping distance of the block?

The main thing is that I have no distance given or spring compression. Just Vo, k, M, and the coefficient of kinetic friction.
 
Physics news on Phys.org
The amount of spring compression is equal to the stopping distance.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top