World's largest guitar - frequency of vibration

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Homework Help Overview

The discussion revolves around a problem related to the fundamental frequency of vibration of strings on the world's largest guitar, specifically focusing on the relationship between wave speed, wavelength, and frequency. The original poster expresses confusion regarding the provided frequency value of 50.0 Hz, which is not explicitly stated in the problem.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between wave speed, wavelength, and frequency, with one participant suggesting the relevant equation. The original poster questions the source of the frequency value provided in the problem.

Discussion Status

The conversation is ongoing, with some participants providing guidance on the relationship between wave speed, wavelength, and frequency. There is an exploration of the original poster's confusion regarding the frequency value, but no consensus has been reached yet.

Contextual Notes

The original poster notes a potential misunderstanding regarding the problem statement, particularly the frequency value of 50.0 Hz, which is not clearly defined in the problem context.

Kimisaishime
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I have a problem on my sheet that is confusing me. The problem states The world's largest guitar, which was built by high school students in Indiana, has strings that are 9.0 long. The fundamental vibration that can be induced on each string has a wavelength equal to twice the string's length. If the wave speed in a string is 9.0 x 10 squared m/s what is the frequency of vibration?

The given is f=50.0 Hz L= 9.0 m

My question is where did they get 50.0 Hz when it's not stated in the problem. Or am I reading the problem wrong.
 
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You are given the wavelength and the wave speed. You must calculate the frequency. What relationship ties wave speed to frequency and wavelength?

(I split this off into its own thread.)
 
um is it the equation speed= wavelength x frequency
 
Exactly. That's all there is to it.
 
starting a new thread

FYI: When you need help with a problem, don't tag your question onto an existing thread--start a new one using the "New Topic" button. (Unless you are working on the exact same problem, of course, or one closely related.)
 
ok thank you
 

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