Write in the form z=x+jy the complex number e^e^j ^=exp

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To express the complex number e^e^j in the form z=x+jy, Euler's formula is applied, resulting in e^{j} = cos(1) + j*sin(1), leading to e^{e^{j}} = e^{cos(1)} * e^{j*sin(1)}. For the equation |z+2|=|z-1|, it describes points equidistant from two fixed points on the complex plane, specifically -2 and 1. By substituting z = x + jy, the equation can be transformed into a quadratic form, revealing constraints on x but not y. The discussion emphasizes the importance of understanding complex numbers in telecommunications. Further exploration of these equations is encouraged for deeper comprehension.
dionys
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Can you help me with the following problems please.
I have a course in telecommunications and i have to understand
complex numbers first.

I can't solve the following exercises:
1) Write in the form z=x+jy the complex number e^e^j
^=exp

2)how i can solve this equation |z+2|=|z-1| and what is the algebraical explanation (z=|z|e^jè|)
 
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So what have you managed to do so far?
 
nothing these are the only exercises of the assignment that i can't do
 
dionys said:
Can you help me with the following problems please.
I have a course in telecommunications and i have to understand
complex numbers first.

I can't solve the following exercises:
1) Write in the form z=x+jy the complex number e^e^j
^=exp

2)how i can solve this equation |z+2|=|z-1| and what is the algebraical explanation (z=|z|e^jè|)
1. Use Euler formula
2. a. |z-2|=|z+1| <-- is it modular or absulute?
b. so what do you think an algebraical form is ? (also use 1.)
 
Hello

e^{j\phi} = \cos\phi + j\sin\phi
\Rightarrow e^{j} = \cos(1) + j\sin(1)
\Rightarrow e^{e^{j}} = e^{\cos(1) + j\sin(1)} = e^{\cos(1)}e^{j\sin(1)}

Can you take this further now?

Cheers
Vivek
 
According to the second equation, viz \|z + 2\| = \|z - 1\| a point is constrained to move on the Gaussian plane such that its distance from a fixed point -2 + j0 equals its distance from another fixed point 1 + j0. Do you know anything else about it or is that it? If you set z = x + jy and solve the resulting algebraic equation (which is quadratic in x), you get something like x = constant, but nothing about y...did you try this?
 
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