Zero Divided By Some Integer n

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Bashyboy
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I tried to prove this claim, as I require it to finish one of my proofs.

By definition, if a,b are integers, with a \ne 0, we say that a divides b if there exists an integer c such that b = ca.

So, n divides 0 means that there exists some integer c such that n = c*0 = 0. But this would contradict the fact that n can't be zero.

What is wrong with this proof?
 
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According to your definition, "n divides 0" means there is some integer c such that 0 = c*n. This differs from what you have written above.
 
Oh, whoops. I always seem to write it backwards. Thanks, I see now!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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