swansont,
thanks for your response..
from the information given, I know that:
dark bands occur at: 2t=m lambda (where t is thickness)
m(order) =230
lambda(in vacuum) = 600nm
from what you mentioned, the light going through the gas chamber will have change wavelengths.. and that...
Gnome,
Your answer was the correct one. I tried your process earlier, but I think I was confusing the theta since it was given in radians as opposed to doing sin theta for the degrees..
Thanks!
Question: One of the beams of an interferometer, as seen in the figure below, passes through a small glass container containing a cavity D = 1.40 cm deep.
When a gas is allowed to slowly fill the container, a total of 230 dark fringes are counted to move past a reference line. The light used...
Question: A set of narrow vertical slits is located a distance D from a screen. The slits are equally spaced and have the same width. The intensity pattern in the figure is observed when light from a laser passes through the slits, illuminating them uniformly. The screen is perpendicular to the...
Q:Spy planes fly at extremely high altitudes (25.3 km) to avoid interception. Their cameras are reportedly able to discern features as small as 5.20 cm. What must be the minimum aperture of the camera lens to afford this resolution? (Use lambda = 550 nm.)
I first found theta.. .052m/2 = .026m...
The question is:
A simple generator has a 655 loop square coil 19.7cm on a side. How fast must it turn in a .490 T field to produce a 110V peak output? give your answer in radians/second
I used V=NBAwsin(wt)
where V = 110, N=655, B=.490, A=.197*.197, w simplifies to 2*pi*f, wt simplifies to...
Given: A proton is accelerated up to KE before it exits into a magnetic field and is deflected.
Question: What voltage battery is required accelerate the proton to that energy?
So I use U = qV
the question is.. what is Q.. is q the charge of the proton being accelerated through the...
I figured it out. I probably spent 4 hours doing this problem (and every variation of solving it under the sun) before I figured out I was taking the Square instead of the square root!
thanks for all of your help!
it is on the outside of these two charges..
X is to the left of Q2 since Q1 is much stronger than Q2 and they are of opposite charges.. thus the picture would look like:
Q1---Q2----X
I set up Etotal=E1 + E2 = 0
thus kQ1/R1^2 = kQ2/R2^2, cancelling out K..
if Q1=3x10^-5 C and is at...
Here is the question: A positive point charge Q1 = 3.00×10-5 C is fixed at the origin of coordinates, and a negative charge Q2 = -8.86×10-6 C is fixed to the x-axis at x = +1.97 m. Find the location of the place along the x-axis where the electric field due to these two charges is zero.
I am...
Here is the question and my solution (Which is wrong..) my question is.. where did I go wrong?
A patient is to be given a blood transfusion. The blood is to flow through a tube from a raised bottle to a needle inserted in the vein. The inside diameter of the 3.97 cm long needle is 0.406 mm...
i've been thinking along the lines of ratios.. but the momentum to energy conversion was screwing me up.. (the equations I was coming up with were rediculous!)
in the end, I just looked at the contribution of mass vs. velocity between momentum and energy to solve it..
so between momentum...
We are doing Cons. of Momentum in my intro to physics class.. and I am stuck on this problem:
An explosion breaks an object into two pieces, one of which has 1.58 times the mass of the other. If 7370 J were released in the explosion, how much kinetic energy did the heavier piece acquire...