Recent content by Muthumanimaran

  1. Muthumanimaran

    B How trapped ions can be used to make Atomic clocks?

    Can someone explain me conceptually how one can use trapped ions to make atomic clocks? My basic understanding of trapped ions is, we can think of an ionized atom which is controlled by electric and magnetic fields. But i am wondering how can one build an atomic clock using trapped ions.
  2. Muthumanimaran

    I Exploring the Physics of LASER: Classical vs Quantum Mechanics

    According to my understanding, classical light source is something we can able to describe using classical electromagnetism. I have this confusion because, when you say LASER, we talk bunch of photons in phase. Does this violate uncertainty principle between phase and photon number...
  3. Muthumanimaran

    I Exploring the Physics of LASER: Classical vs Quantum Mechanics

    My question is the physics behind the LASER such as stimulated emission can be only explained by quantum mechanics only. We can represent LASER as coherent state in quantum mechanics only. Then how can we say LASER can be thought of a classical light source?
  4. Muthumanimaran

    Comparing cicular motion to the motion of a pendulum

    and also wondering what is the significance of the term $$E-\vec{\omega}.\vec{J}$$ why E and J also are individually not constants of motion here?
  5. Muthumanimaran

    Comparing cicular motion to the motion of a pendulum

    Yes I made a small mistake, there is factor of 2 in the second term $$\vec{\omega}.\vec{J}=mR^2\omega(\omega+\dot{\phi})+mR^2\omega^2\cos(\phi)$$ okay now I understood, I took canonical conguate momentum as my angular momentum with respect to axis of rotation, so J has a different expression...
  6. Muthumanimaran

    Comparing cicular motion to the motion of a pendulum

    The coordinates of the mass 'm' is $$x=R\cos(\omega{t})+R\cos(\omega{t}+\phi)$$ $$y=R\sin(\omega{t})+R\sin(\omega{t}+\phi)$$ Where $\phi$ is the angle of the particle with respect to coordinate system attached to the circle with origin at center of the circle. Since particle is not acted upon...
  7. Muthumanimaran

    B Time average value of Spin operator

    Im satisfied with the Griffith's explanation for the above expression, but out of curiosity I am looking for the mathematical proof of the same expression. While searching internet about this question, I saw "Wigner Eckart Theorem" could be used to find this expectation value, but I don't know...
  8. Muthumanimaran

    B Time average value of Spin operator

    From the book Introduction to Quantum Mechanics by Griffiths,. In the section 6.4.1 (weak field zeeman effect) Griffiths tells that the time average value of S operator is just the projection of S onto J while finding the expectation value of J+S $$S_{avg}=\frac{(S.J)J}{J^2}$$ How to prove this?
  9. Muthumanimaran

    How do I calculate work and heat in a PV diagram for an ideal monoatomic gas?

    Without knowing the specific heat of the gas how do I calculate the change in internal energy from A to B? Workdone = P(VB-VA), is it just enough to plug these values to find the heat transfer from A to B? for B to C is an isotherm, so workdone is equal to heat right?
  10. Muthumanimaran

    How do I calculate work and heat in a PV diagram for an ideal monoatomic gas?

    P=1 atm V=20lit at point C and T=PV/R So T=20/R K at point C Pressure at B is 4 atm T = 20/R So V=5 lit
  11. Muthumanimaran

    How do I calculate work and heat in a PV diagram for an ideal monoatomic gas?

    From A to C it is not a cyclic process, so the change in internal energy cannot be zero (from A to C), then how to find the heat absorbed by the gas?
  12. Muthumanimaran

    How do I calculate work and heat in a PV diagram for an ideal monoatomic gas?

    Oh, I got it now. I just need to calculate the work done from A to B and B to C and sum it up? Am I right?
  13. Muthumanimaran

    Bond Strength and Force constant

    Homework Statement Homework EquationsThe Attempt at a Solution (a) Total energy is $$E=\frac{-e^2}{4\pi\epsilon_{0}R}-\frac{B}{R^{5/6}}$$ Taking derivative of E with respect to R and equating it to zero when R=R0 yields, i.e, $$\frac{dE}{dR}{\bigg|}_{R=R_0}=0$$ when R=R0 yields...
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