# Recent content by Xels

1. ### PH of buffer; no Ka/Kb given

Thank you; this is the point I was getting hung up on. Knowing that I'm not expected to deduce the Ka I'm willing to resort to known values.
2. ### PH of buffer; no Ka/Kb given

Homework Statement A 100.0mL buffer solution is 0.175M in HClO and 0.150M in NaClO. Find the pH of the solution. Homework Equations Ka=10^-pH ([H30+][A-])/([HA]) -log([H30+]) = pH The Attempt at a Solution [HClO] [H3O+] [ClO-] I .175 0 .150...
3. ### Equilibrium Partial Pressure

After much reworking I found my error. Thanks for your input Borek.
4. ### Equilibrium Partial Pressure

I got +/- x by solving (x*x)/(.725-x)^2 quadratically. I'm not sure where to go past this to find partial pressures.
5. ### Equilibrium Partial Pressure

Homework Statement At 600 K the equilibrium constant is 38.6 for the reaction 2 HI(g) <--> H2(g) + I2(g) Start with a pressure of 0.725 atm consisting of only HI(g) at 600 K. Calculate the equilibrium partial pressures of HI, H2 and I2. Homework Equations K=[C]^n[D]^n/[A]^n Qp =...
6. ### Circuit Power

After punching it through again I got the correct answer; I went wrong in the way I set up Hz; punching in 47.5^-1, since Hz = S^-1; but thats redundant...
7. ### Circuit Power

Homework Statement A generator with an rms voltage of 130V is connected in series to a resistor 3.65k\Omega and a capacitor 3.00\muF. Using the frequency found in part A (47.5Hz), find the average power consumed by this circuit. \phi = 17degrees Homework Equations Latex isn't...
8. ### Resistance in a light bulb

Hrmm... P = V2/R PR = V2 R = V2/P R = 160\Omega That works better huh? Thank you!
9. ### Resistance in a light bulb

Homework Statement A "90-watt" light bulb uses an average power of 90W when connected to an rms voltage of 120V . What is the resistance of the lightbulb? Homework Equations Pav=(V2rms/R) The Attempt at a Solution 90W = 120V2/R 90W/120V2 = R R = .00625\Omega
10. ### Current through resistors

Homework Statement Consider the circuit shown in the figure . Suppose the four resistors in this circuit have the values R1 = 12 \Omega, R2 = 6.4 \Omega, R3 = 7.0 \Omega, and R4 = 13 \Omega, and that the emf of the battery is \epsilon = 18V . A. Find the current through each resistor...
11. ### Electric Field & Point Charge Potential Energy

Wrong equation used: \DeltaU=q0Ed \DeltaU=8x10-6C* -8.5x105N/C * 6m = -40.8J
12. ### Electric Field & Point Charge Potential Energy

Homework Statement A uniform electric field of magnitude 8.5×105 N/C points in the positive x direction. Find the change in electric potential energy of a 8.0 \muC charge as it moves from the origin to the point (6.0 m , 0). Homework Equations 1 N/C = 1 V/m \DeltaU = q\DeltaV E =...
13. ### Electric Field Magnitude

Great, thats exactly the kick I needed. Thank you.
14. ### Electric Field Magnitude

Homework Statement The figure shows an electron entering a parallel-plate capacitor with a speed of 5.4×106m/s. The electric field of the capacitor has deflected the electron downward by a distance of 0.618cm at the point where the electron exits the capacitor. Find the magnitude of the...
15. ### Electrostatic Force between point charges

Thanks so much for the help