Whats the materials specific heat capacity?

AI Thread Summary
The discussion revolves around calculating the specific heat capacity of a material after raising its temperature by 400 degrees F using 150 kcal of heat. The initial answer proposed was 1.35 kcal/kg°C, which was later corrected to 0.34 kcal/kg°C. The formula used for the calculation was Q = mcΔT, with some confusion regarding temperature conversion from Fahrenheit to Celsius. Participants clarified the conversion process and confirmed the corrected answer. The conversation highlights the importance of accurate unit conversion in thermodynamic calculations.
Dx
Hello,

150kcal of heat raises the temp of 2.0kg of material by 400 degrees F. Whats the materials specific heat capacity?

I cam up with 1.35 kcal/kg degrees C. is this correct?

Thanks!
Dx :wink:
 
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Dx,

That's not what I get. Can you show me what you did?

Thanks,
 
I used some substitution

Originally posted by Tom
Dx,

That's not what I get. Can you show me what you did?

Thanks,

No problem, Tom! I meant to say .34 kcal/fg oC was my answer sorry that's another problem i am working on but i got it wrong anyways, lol.

I used the formula [del]Q = mc [del]T and substituted.
c = 150kcal / (2kg)* (190oC) =
.34 kcal

i figured it was .34 since when i converted from F to C i rounded the number so then I usd scientific notation to conclude to this answer.
I am sorry but I have reworked this problem many times erasing and adding to it so excuse me if its not exact but you can see I am really trying here.
Thanks!
Dx
 
OK, that's what I got too.

I was thinking you had made a mistake converting ΔTF to ΔTC (because you have to multiply by 5/9), but then I reworked the problem by making that mistake, and I still did not get your answer.

Oh well, that's cleared up now.
 
TY Tom

Just wanted to say thanks!
 

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