Help needed - Spinning wheel, torque, angular acceleration.

AI Thread Summary
The discussion revolves around a physics problem involving a spinning cylindrical wheel that begins to decelerate before being stopped by a metal rod. The user calculated the angular deceleration to be -3477 rad/s² and determined the moment of inertia using the parallel axis theorem, yielding a value of 4.844 x 10^-7 kg·m². The torque was computed as -0.00956 N·m, with a corresponding linear force of 1.593 N, assuming the rod is inserted perpendicular to the wheel. Concerns were raised about the applicability of rotational kinematic equations due to the non-constant deceleration caused by the rod's insertion. The user seeks feedback on their calculations and methodology.
Fjolvar
Messages
156
Reaction score
0

Homework Statement


There is a spinning cylindrical wheel of mass 0.013 kg at a given constant angular velocity ωo (78.54 rad/s). The wheel instantaneously begins to decelerate at an unknown constant deceleration α. From when it begins to decelerate, the wheel spins a distance of θ (0.887 radians) before a metal rod is placed inside of the wheel at a distance of 0.6cm radius from the origin, bringing the wheel to a stop by making contact with one of the spokes BEFORE the wheel completely decelerates (so the wheel is still in motion as the rod is placed inside). What is the torque and linear force exerted on the metal rod when stopping the wheel?

Homework Equations


θ = ωot + (1/2)α t2
ω2 = ωo2 + 2α (θ-θo)
I = (1/2)Mr2
L = r x p = r x mv = Iω
τ = I*α = r x F = r*F*sinθ

The Attempt at a Solution


Okay, so I chose to use rotational kinematic equations to determine the torque value.

First I calculated the angular deceleration by using the rotational kinematic equation, assuming ω=0 and θo=0 :
ω2 = ωo2 + 2α (θ-θo). This gave me α = -3477 rad/s2.

Then I calculated the moment of intertia of a cylinder using the parallel axis theorem about the point of contact, I = Icm + mr2, which gave me a value of 4.844*10-7.

Finally plugging I and α into the equation for torque τ = I*α, I got τ = -0.00956 N*m and force value of 1.593 N using the equation τ= r*F*sinθ (assuming θ to be 90 degrees since the rod is inserted perpindicular to the wheel).

I would greatly appreciate any feedback on my methods of solving this problem, since I'm unsure if this answer or method is correct. Thank you for your time.
 
Last edited:
Physics news on Phys.org
I just made the observation, since the rod is placed into the wheel before it fully decelerates to zero, this makes for non-constant deceleration and thus makes the rotational kinematic equations unuseable correct?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top