Calculating angular speed out of tangential speed

AI Thread Summary
To find the tangential speed of particle B, it is established that particle A has a tangential speed of 2 m/s at a radius of 5 m, giving it an angular speed w1. Since particle B has a radius of 10 m and an angular speed w2 that is twice w1, the calculation shows that the tangential speed v2 of particle B is 8 m/s. The relationship between tangential speed and radius confirms that as the radius doubles, the tangential speed increases proportionally when angular speed is adjusted accordingly. The final conclusion is that particle B's tangential speed is indeed 8 m/s, consistent with the given conditions.
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Homework Statement



A particle A is moving at constant tangential speed v1 = 2m/s on a circumference of radius r1 = 5m.
Particle B is performing a uniform circular motion on a circumference whose radius is r2 = (2)r1.
Find the tangential speed of v2 of particle B assuming that the angular speed w2 of particle B is twice the angular speed w1 of particle A


Homework Equations


Tangential speed at 10m from the axis point is 2 times the tangential speed at 5m from the axis.


The Attempt at a Solution



v1=2m/s at 5m from the axis of rotation
IF particle B was rotating at the same angular speed...v2=4m/s
BUT w2 = 2w1 SO v2=8m/s
 
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That looks correct.

v/r = 2/5 = ω

2ω = 4/5

v = ω *r = 4/5*10 = 8
 
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