Finding electric potential using charge density

Thread starter AMMax
Start date Feb 23, 2010
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Charge Charge density Density Electric Electric potential Potential

AI Thread Summary

To find the electric potential of a 5 cm radius conducting sphere with a surface charge density of 2x10^-6 C/m^2, the equation V = K(q/r) is applied. The calculated electric potential is 1.12 x 10^4 V, which some participants initially feel may be too straightforward. However, it is confirmed that the calculation is indeed correct and not missing any complexities. The discussion emphasizes that the solution is valid and straightforward for this scenario. The electric potential relative to the potential far away is accurately determined.

Feb 23, 2010

AMMax

Homework Statement

a 5 cm radius conducting sphere has a charge density of 2x10^-6 C/m^2 on its surface. Its electric potential, relative to the potential far away is?

Homework Equations

I used V= K(q/r)

The Attempt at a Solution

Using the above equation I got 1.12 x 10^4. This seems too easy. I think I am missing something here.

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Feb 23, 2010

kuruman

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You are not missing anything. It is that easy.

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