Question about stress and strain

AI Thread Summary
To determine the minimum diameter of a wire that can support a 100N load without exceeding the elastic limit of 1.6 x 10^8 Pa, the stress formula S = F/A is used, where A is the cross-sectional area of the wire. The area for a circular wire is calculated as A = π(d/2)^2, which can be rearranged to find the diameter. By substituting the known values for stress and force into the equation, the diameter can be solved. The discussion emphasizes the importance of correctly applying the formulas to arrive at the solution. Understanding these calculations is crucial for material strength assessments in engineering applications.
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Homework Statement


The elastic limit for a type of material is 1.6 x 10^8 Pa.Determine the minimum diameter if a wire which is made of this material so that it can support a load of 100N without the stress exceeding the elastic limit.


Homework Equations


elastic limit=stress
=F/A
1.6 x 10^8=100/ (pie)d^2
I can't get the answer.please help

The Attempt at a Solution

 
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In your S = F/A formula, replace A with the area of the circular wire.
Solve for the radius or diameter.
Put in the numbers for S and F.
 

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