Air Pressure Difference in a 13m High Gymnasium

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SUMMARY

The discussion focuses on calculating the air pressure difference between the floor and ceiling of a 13-meter high gymnasium. The calculations provided indicate that the air pressure at the floor, calculated as P(bottom) = 101463.072 Pa, is greater than the pressure at the ceiling, P(top) = 101300.000 Pa. The resulting percentage difference in air pressure is 0.161%. The accuracy of the calculation hinges on the correct value of air density used in the formula.

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  • Familiarity with the ideal gas law and its application in pressure calculations.
  • Knowledge of air density values at standard conditions.
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This discussion is beneficial for physics students, engineers, and anyone interested in understanding the principles of fluid mechanics and air pressure variations in large spaces.

jason_r
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A gymnasium is 13.0 m high.

By what percent is the air pressure at the floor greater than the air pressure at the ceiling?
 
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so far i have

P(bottom)=(1.013 x 10^5) + (1.28)(9.8)(13)
P(bottom)=101463.072
P(top)=101300.000

P(bottom)/P(top)=0.161%
is that correct?
 
Hi jason_r,

jason_r said:
so far i have

P(bottom)=(1.013 x 10^5) + (1.28)(9.8)(13)
P(bottom)=101463.072
P(top)=101300.000

P(bottom)/P(top)=0.161%
is that correct?

That looks right to me (as long as your air density is correct).
 

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