Air Pressure Difference in a 13m High Gymnasium

AI Thread Summary
The discussion focuses on calculating the air pressure difference between the floor and ceiling of a 13-meter high gymnasium. The participant calculates the pressure at the bottom using the formula P(bottom) = (1.013 x 10^5) + (1.28)(9.8)(13), resulting in 101463.072 Pa, while the pressure at the top is 101300.000 Pa. The calculated percentage difference in air pressure is 0.161%. Another participant confirms the calculations are correct, contingent on the accuracy of the air density used. The conversation emphasizes the importance of precise measurements in pressure calculations.
jason_r
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A gymnasium is 13.0 m high.

By what percent is the air pressure at the floor greater than the air pressure at the ceiling?
 
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so far i have

P(bottom)=(1.013 x 10^5) + (1.28)(9.8)(13)
P(bottom)=101463.072
P(top)=101300.000

P(bottom)/P(top)=0.161%
is that correct?
 
Hi jason_r,

jason_r said:
so far i have

P(bottom)=(1.013 x 10^5) + (1.28)(9.8)(13)
P(bottom)=101463.072
P(top)=101300.000

P(bottom)/P(top)=0.161%
is that correct?

That looks right to me (as long as your air density is correct).
 
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