PNP transistor saturation voltage

In summary, the conversation is about troubleshooting a power supply and circuit that uses a PNP transistor to energize a 5V relay. The design worked initially but suddenly stopped working with a high VCE. A diode was suggested to be added to the CE junction of the transistor. However, after ordering a new transistor and adding the diode, the circuit still did not work. Further testing revealed that only one of the four power supplies could successfully power the relay. The problem was determined to be somewhere else in the circuit, and the suggestion was made to test grounding the base of the transistor to see if the relay would turn on.
  • #1
StealthRay
51
0
Hi,

Anyone here can tell me how to control the saturation voltage of a pnp transistor?

I was actually doing a project and my design using a pnp transistor to energize a 5V relay.Since I am using 5V supply,I can't afford to drop too much voltage at VCE of the transistor.

The design was tested and it worked fine for the past 2 weeks.I was able to get 3.5V at the relay which was enough to energize the 5v relay.

Strangely,the circuit wasnt working yesterday and there was only 0.7V at the relay coil which the VCE of the transistor taking a large chunk of the voltages.

Anyone can advice what could be the reason the VCE suddenly so high?I increase the Ib to 6mA but still couldn't get the VCE down.

Or something wrong with the relay resulting the VCE so high?I tested the relay by directly applying power to it and it worked fine.

Or it could be the transistor itself was damaged and acted strangely.

Please advice.Thank you.
 
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  • #2
Hi Stealthray-
One thing to be careful about when driving relays with transistors is that the relay coil has a lot of inductance L. When the transistor (I presume open collector) suddenly cuts off the relay coil current, there is a large dI/dt. Thus there is often tens (or more) of volts across the transistor from collector to emitter (recall V = L dI/dt) of both polarities, and this can wipe out the transistor. Put a reverse biased diode fron the collector to the emitter.
Bob S
 
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  • #3
Bob S said:
Hi Stealthray-
One thing to be careful about when driving relays with transistors is that the relay coil has a lot of inductance L. When the transistor (I presume open collector) suddenly cuts off the relay coil current, there is a large dI/dt. Thus there is often tens (or more) of volts across the transistor from collector to emitter (recall V = L dI/dt) of both polarities, and this can wipe out the transistor. Put a reverse biased diode fron the collector to the emitter.
Bob S

Hi Bob,

TransistorCE.jpg


I am not really sure if I got what you meant.Refer to the diagram,I put a diode at the CE junction of the transistor.Is this the right way of connecting the diode to the transistor CE junction?

Thank you.
 
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  • #4
Troubleshooting power supply and circuit

Hi,

I decided to make a new thread on this since the last thread did not solve my problem.

https://www.physicsforums.com/showthread.php?p=2392499#post2392499

TransistorCE.jpg


Refer to the circuit diagram,where in my old thread,the CE junction of the transistor is taking all the voltages and there is less than 1V voltage on my 5v power relay.It seems that the transistor was not working.I ordered new transistor and retested the circuit with a diode added at the CE junction.Sadly,it was not working.The relay still did not have enough voltage to energize and most of the voltage was at the CE junction of the transistor.

Now here is the problem which I found out:

I have 4 DC variable power suply which I use to do the testing.I measured all the power supply with a multimeter and they looked good.

During the testing,I found out that only 1 power supply which can power up my circuit and energize the relay.

Another 2 power supply though provide the voltage correctly could not energize the relay as most voltage is applied to the CE junction.When I use the IR transmitter to trigger the base of the transistor,there was clicking sound from the relay but it could not energize.

Another 1 power supply goes into fault (the same condition if I short circuit it) when I trigger the base of the transistor.

As you can see,only 1 power supply can be used.Although,all the power supply looks fine and produce accurate voltages as measured by my voltmeter,only 1 can be used to work correctly on my circuit.

I was wondering what is the real problem here?Why the same power supply (from same manufacturer) could produce different effect on my circuit board.Could it be something wrong with my circuit?

Please advice.

Thank you.
 
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  • #5


- The probem is not in the part of the circuit that you posted, it's somewhere else.

- You don't need the CE diode, it does nothing in your circuit. The other diode is needed however.

- What is the part number of the transistor?

- Show the cicuit of the base drive of the transisitor.

- Do your power supplies have (adjustable) current limits?
 
  • #6


uart said:
- The probem is not in the part of the circuit that you posted, it's somewhere else.

- You don't need the CE diode, it does nothing in your circuit. The other diode is needed however.

- What is the part number of the transistor?

- Show the cicuit of the base drive of the transisitor.

- Do your power supplies have (adjustable) current limits?

Hi,

Attached is the full circuit diagram which I use in the testing.

scan-1.jpg


I am using transistor pnp 2N2905A and the ir receiver is TSOP1238 Vishay.

Regarding the power supply,yes it is adjustable.I think it has more than 1A rating.Out of the 4 power supply,only 1 of them can be used to on the relay when the IR receiver was triggered.

Thank you.
 
  • #7


I'm sure you know, in an PNP, you have to let the current out of the base in order to turn it on.

you can do a quick test, and simply ground the base with a crocodile click and see if the relay will turn on.

if it does, then the problem is somewhere else.
 
  • #8


waht said:
I'm sure you know, in an PNP, you have to let the current out of the base in order to turn it on.

you can do a quick test, and simply ground the base with a crocodile click and see if the relay will turn on.

if it does, then the problem is somewhere else.

Ok,I will try it tomorrow.

But the thing that puzzled me was why 1 of the power supply can power up the relay while the other 3 power supply cant. And I tested all the 4 power supplies on the IR transmitter and they all worked fine.

For 2 of the power supplies,most of the voltages were at the ce junction and only 0.7V was dropped at the coil.The weird thing was when I point the transmitter to the receiver,there were non stop clicking sound from the relay as it was on and off non stop. but the measurement from voltmeter showed it did not energize and no connection at the NO/COM pin.

Another power supplies showed short circuit fault when I point my transmitter to the receiver.

The last power supply was able to energize the relay and work correctly.
 
  • #9


then in that case, the power supplies have adjustable current limit. somebody was messing around with them earlier and lowered the current limit.

if the power supply is analog, current limit is not hard to find, if it's digital you have to go the menu and find current limit.
 
  • #10


waht said:
then in that case, the power supplies have adjustable current limit. somebody was messing around with them earlier and lowered the current limit.

if the power supply is analog, current limit is not hard to find, if it's digital you have to go the menu and find current limit.

Yes,there are 2 knobs at the power supply,one which is the voltage and the other current.

In all my testing and lab work,the lecturer told us to turn the current knob just a little bit.And then turn the voltage knob to the voltage we want.

Are you saying,that I need to turn more on the current knob to raise the current limit.

If that is the case,if I was indeed set a low current limit,and my relay will probably need:

5V/50ohms = 0.1A, then this will result in 4V++ at the CE junction and only 0.7V at the relay coil?

Thank you.
 
  • #11


StealthRay said:
Ok,I will try it tomorrow.

But the thing that puzzled me was why 1 of the power supply can power up the relay while the other 3 power supply cant. And I tested all the 4 power supplies on the IR transmitter and they all worked fine.

For 2 of the power supplies,most of the voltages were at the ce junction and only 0.7V was dropped at the coil.The weird thing was when I point the transmitter to the receiver,there were non stop clicking sound from the relay as it was on and off non stop. but the measurement from voltmeter showed it did not energize and no connection at the NO/COM pin.

Another power supplies showed short circuit fault when I point my transmitter to the receiver.

The last power supply was able to energize the relay and work correctly.
uart said:
- Do your power supplies have (adjustable) current limits?

Also, do you know what an adjustable current limit is and how to use it?
 
  • #12


uart said:
Also, do you know what an adjustable current limit is and how to use it?

I have no idea what is that for.But I think it limits the output current of the supply.

I measured the relay coil when pnp transistor turns on and it showed 0.7V.

So I = 0.7V/47ohms = 14.9 mA.

Can I say this is the max current that the power supply produced based on the current knob setting?If I turn the knob more,Will I get more current and this increase the voltage at the relay coil and lower the voltage at the CE junction?

Thank you.
 
  • #13


StealthRay said:
I have no idea what is that for.But I think it limits the output current of the supply.

I measured the relay coil when pnp transistor turns on and it showed 0.7V.

So I = 0.7V/47ohms = 14.9 mA.

Can I say this is the max current that the power supply produced based on the current knob setting?If I turn the knob more,Will I get more current and this increase the voltage at the relay coil and lower the voltage at the CE junction?

Thank you.

Yep, that's the trick. :) It sounds like some of the power supplies simply have the current limits set too low for your circuit.

Basically the current limit is there (on a good lab power supply) to try and help prevent you damaging things if you make a short or other mistake with in your experiment or prototyping exercise. You should always set the current limit before you start working on a given circuit based on the approx maximum current that you expect the circuit will need. In this case I suggest you should set the current limit to approx 200mA.

To set the current limit you should first adjust the voltage to just a few volts and the current limit to near zero. Then apply a short to the supply terminals* and slowly increase the current limit until you get the desired value. Then just remove the short, set your voltage and start your experiment.

* Some power supplies have a "set current" switch (or button) which does this for you automatically so you don't need an actual external short.
 
  • #14


uart said:
Yep, that's the trick. :) It sounds like some of the power supplies simply have the current limits set too low for your circuit.

Basically the current limit is there (on a good lab power supply) to try and help prevent you damaging things if you make a short or other mistake with in your experiment or prototyping exercise. You should always set the current limit before you start working on a given circuit based on the approx maximum current that you expect the circuit will need. In this case I suggest you should set the current limit to approx 200mA.

To set the current limit you should first adjust the voltage to just a few volts and the current limit to near zero. Then apply a short to the supply terminals* and slowly increase the current limit until you get the desired value. Then just remove the short, set your voltage and start your experiment.

* Some power supplies have a "set current" switch (or button) which does this for you automatically so you don't need an actual external short.

Thank you so much for helping me to troubleshoot and find out the root cause of the problem.
 
  • #15


StealthRay said:
Yes,there are 2 knobs at the power supply,one which is the voltage and the other current.

In all my testing and lab work,the lecturer told us to turn the current knob just a little bit.And then turn the voltage knob to the voltage we want.

That would have been because the circuits you were working with only needed a little bit of current. Now this one needs a bit more, that's all.

Edit. I hadn't seen the above reply when I posted this. I see you fully understand the current limit thing now. :)
 
  • #16


uart said:
That would have been because the circuits you were working with only needed a little bit of current. Now this one needs a bit more, that's all.

Edit. I hadn't seen the above reply when I posted this. I see you fully understand the current limit thing now. :)

By the way,there are 3 terminal at the power supply outlet, -ve ,ground ,+ve

What is the difference connecting to -ve,+ve and +ve and ground?

I measure the voltage and they are all the same.

Thank you.
 
  • #17


Ground is connected to the power system earth. For simple circuits with just a single supply you'll usually have "-ive" as your zero volt reference and in such cases it's often a good idea to also have this connected to the system ground. Instrumentation (like scope or signal generator for example) will usually have a ground reference so once you connect them to your circuit it will be grounded anyway.

Only in certain circumstances will you want to have your power supply isolated from ground and a good power supply should give you that option.
 
  • #18


uart said:
Ground is connected to the power system earth. For simple circuits with just a single supply you'll usually have "-ive" as your zero volt reference and in such cases it's often a good idea to also have this connected to the system ground. Instrumentation (like scope or signal generator for example) will usually have a ground reference so once you connect them to your circuit it will be grounded anyway.

Only in certain circumstances will you want to have your power supply isolated from ground and a good power supply should give you that option.

Thank you for all the info.
 
  • #19


StealthRay said:
Hi,

I decided to make a new thread on this since the last thread did not solve my problem.

Multiple posting the same question is not allowed. I've merged your two threads into one here.
 
  • #20


berkeman said:
Multiple posting the same question is not allowed. I've merged your two threads into one here.

My apology on that.I thought making a new thread for a new detected problems on the same issue might make the question more straightforward and simple.

I will not repeat the same mistake again:wink:
 
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  • #21
No worries. Looks like it's all sorted out now? Or are there any additional issues?
 
  • #22
Yes,I just did some testing today and everything was running perfectly.It was the current limiter of the power supply that was giving the problem.

Thank you Bob, UART and waht for spending their precious time helping me out.
 
  • #23
I think that the very first thing you should be sure of is the power supply. Without a decent supply nothing will go right.
So don't go looking for a supply that is thr 'right' size, you are in a "home-made" circuit application here and tuning things real fine ain't a practical option.
Get a supply that can comfortably handle twice your anticipated load, and see to it that it is well regulated and reliable,
Now address the transistor problem. My own practice in one-off situations is to use a transistor that is considerably over-rated for the job. You want to saturate your transistor, so give it heaps. If you can't get enough current out of your receiver to do the job of saturation, make up a darlington pair, dropping all the current from the emitter of the first transistor into the base of the second.


You would do well (as would every electronics hobbyist) to thoroughly read Horowitz & Hill's "The Art Of Electronics" which is the best text on the subject ever written.

Please can I say that I'm a bit scared of hooking this kind of stuff onto expensive equipment, I like to isolate the expensive gear behind an opto coupler.
 

1. What is the definition of saturation voltage in a PNP transistor?

Saturation voltage in a PNP transistor refers to the voltage at which the transistor is fully turned on and the collector current reaches its maximum value. This is the point at which the transistor acts as a short circuit between the collector and emitter terminals.

2. How does the saturation voltage differ from the cutoff voltage in a PNP transistor?

The cutoff voltage in a PNP transistor is the voltage at which the transistor is completely turned off and no current flows between the collector and emitter terminals. On the other hand, the saturation voltage is the voltage at which the transistor is fully turned on and maximum collector current flows.

3. What factors affect the saturation voltage of a PNP transistor?

The saturation voltage of a PNP transistor can be affected by several factors, such as the collector current, base current, temperature, and the characteristics of the transistor itself. The type of load connected to the collector terminal can also impact the saturation voltage.

4. How is the saturation voltage of a PNP transistor calculated?

The saturation voltage of a PNP transistor can be calculated using the following formula: Vsat = Vbe + (Ic / β) * (Rc + RL), where Vbe is the base to emitter voltage, Ic is the collector current, β is the current gain of the transistor, and Rc and RL are the resistances connected to the collector and load, respectively.

5. How can the saturation voltage of a PNP transistor be reduced?

The saturation voltage of a PNP transistor can be reduced by increasing the base current, using a transistor with a lower current gain, reducing the load resistance, or using a transistor with a smaller Vbe. Additionally, keeping the transistor at a lower temperature can also help reduce the saturation voltage.

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