What is the Work Done by Various Forces on a Bucket Moving with a Broom Stick?

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The discussion focuses on calculating the work done by different forces acting on a 2.0kg bucket being pushed with a broom stick at a 60-degree angle. The broom stick exerts a force of 100N, while a constant frictional force of 10N opposes the motion over a distance of 5.0m. The work done by the horizontal component of the broom stick's force and the frictional force is calculated using the formula W=F·d. Additionally, the resultant horizontal force is considered to determine the overall work done. A suggestion is made to draw a free body diagram to visualize the forces and calculate the net horizontal force effectively.
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A Child uses a broom stick to push a 2.0kg bucket of water across a floor. The Broom Stick is held at an angle of 60 degrees to the horizontal and exerts a force of 100N on the bucket. The bucket is initially at rest and encounters a constant frictional force of 10N while moving a distance of 5.0m. Assume the g is 9.8m/s/s, and that the effects of air resistance are negligible.

For the 5.om distance, calculate the work done by:
A) the horizontal component of the 100N Force

B) The frictional Force

C) The Resultant horizontal Force
 
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Have you tried drawing a free body diagram of the forces involved and finding the net horizontal force?

Use W=F\cdot d to calculate the work.
 
Last edited:
Thread 'Variable mass system : water sprayed into a moving container'

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