Ideal Gas Law Question: Solving for Volume at Surface

  • Thread starter Thread starter Borat321
  • Start date Start date
  • Tags Tags
    Gas Ideal gas
AI Thread Summary
To solve for the volume of the air bubble as it rises from 32 m to the surface, the ideal gas law (PV=nRT) must be applied, considering changes in pressure and temperature. At 32 m depth, the pressure is calculated to be 4.2 atm, and the initial volume is 12 cm³ (0.012 L) at 5°C (278 K). Upon reaching the surface, the pressure drops to 1 atm and the temperature increases to 25°C (298 K). The correct approach involves rearranging the ideal gas law to find the final volume, ensuring all variables are accurately accounted for. The final volume can be determined by substituting the known values into the equation.
Borat321
Messages
5
Reaction score
0
Here's an ideal gas law question:

A scuba diver is 32 m below the surface of a lake, where the temperature is 5°C. He releases an air bubble with a volume of 12 cm^3. The bubble rises to the surface, where the temperature is 25°C. What is the volume of the bubble right before it breaks the surface? (Hint: Remember that the pressure also changes.)

I thought it would be the following:

Initial:
Pressure @ 32m = 4.2atm, since 10m=1atm under water
12cm^3=.012 litres
5C= 278K

Final:
Pressure @ 0m = 1atm
V= unknown
25C= 298K

Then, use PV/T=PV/T... but apparently it's wrong - does anyone know why?
 
Physics news on Phys.org
seems right, what's the correct answer?
 
Should be fine, all you have to do is rearrange the final equation you wrote for the second volume and plug the numbers in.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Thread 'Egg Drop Challenge! Need ideas for winning designs'

I was thinking using 2 purple mattress samples, and taping them together, I do want other ideas though, the main guidelines are; Must have a volume LESS than 1600 cubic centimeters, and CAN'T exceed 25 cm in ANY direction. Must be LESS than 1 kg. NO parachutes. NO glue or Tape can touch the egg. MUST be able to take egg out in less than 1 minute. Grade A large eggs will be used.
View full post »

Similar threads

Why must we use absolute temperature for the Ideal Gas Law?
Replies
10
Views
3K
Why is temperature constant after gas has expanded?
Replies
33
Views
2K
Incompatibility between ideal gas equations of state
Replies
2
Views
2K
Ideal Gas Law and Pressure at 80°C
Replies
2
Views
3K
Internal Energy of an Ideal Gas
Replies
4
Views
2K
What would be a real-life example of the ideal gas law?
Replies
3
Views
9K
Proof question related to the Ideal Gas Law
Replies
8
Views
2K
Calculations using the Ideal Gas Law
Replies
2
Views
2K
Closed cycle of an ideal gas
Replies
3
Views
1K
Effect of temperature on surface tension
Replies
2
Views
1K

Hot Threads

Recent Insights

Back
Top