Calculating Work with Electric Field & Charge

AI Thread Summary
To calculate the work done in moving a charge of 2.0 microC in a uniform electric field of intensity 4.0*10^5 N/C along a path at a 60° angle, the formula W = E*q*d*cos(theta) is applied. The calculated work is 0.08 J, using the values provided. The angle and formula used in the calculation are confirmed to be correct. The discussion focuses on verifying the accuracy of the approach taken in solving the problem. Overall, the calculation and methodology are validated as appropriate for the given scenario.
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Homework Statement



A charge of 2.0 microC is located in a uniform electric field of intensity 4.0*10^5 N/C. How much work is required to move this charge 20 cm along a path making an angle of 60° with the electric field?


a.0.14 J

b.0.34 J

c.80 mJ

d.14 J

e.8.0 J


Homework Equations




See below.

The Attempt at a Solution



W = E*q*d*cos theta = (4.0*10^5 N/C)*(2.0*10^-6 C)*(0.2 m) *cos(60) = 0.08 J

I just wanted to know if the angle and formula that I used are correct.

Thanks.
 
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Yes, it's correct.
 
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