Simple Capacitance Problem: Teflon-Filled Parallel-Plate Capacitor Calculation

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The discussion revolves around calculating the capacitance and maximum voltage for a Teflon-filled parallel-plate capacitor with specified dimensions. The insulation thickness is clarified as the separation between the plates, which is crucial for determining capacitance using the formula C = (constant)(A/d). Participants reference a DuPont data sheet for Teflon's electrical properties to aid in calculations. The dielectric nature of Teflon simplifies the process of finding both capacitance and voltage. Ultimately, understanding the role of insulation thickness as plate separation is key to solving the problem.
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Homework Statement



For a TeflonTM-filled parallel-plate capacitor having a plate area of 175 cm2 and insulation thickness of 0.0500 mm, determine the following:

a.)capacitance
b.)max volatge

Homework Equations



C = Q/V

C = (constant)(A/d)

The Attempt at a Solution



I understand the gist of this problem but I don't understand what the "insulation thickness" is supposed to do in this problem. Please help! thanks.
 
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I would read it as Teflon filled and the insulation thickness then would be the separation of the plates.

Not sure what resources you are supposed to employ to determine the properties of the Teflon in the problem, but here is a data sheet from DuPont for the electrical properties.
http://www2.dupont.com/Teflon_Industrial/en_US/tech_info/techinfo_compare.html
 
Yeah I see now. The Teflon acts as a dielectric and from there it isn't too hard to find the Voltage and Capacitance. Thanks a lot again!
 

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