How Do You Solve a Physics Problem Involving Two Masses and a Pulley?

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The discussion focuses on solving a physics problem involving two masses and a pulley system. The problem requires drawing free-body diagrams and calculating tensions in both the horizontal and vertical sections of the string. The tension in the horizontal section is determined to be 0.75m2g, while the vertical section's tension is expressed in terms of m1 and m2. The unknown mass m1 is derived from the relationship between the tensions but presents challenges in simplification. The calculations highlight the interplay between the masses, tension, and gravitational acceleration in the system.
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Homework Statement



An unknown mass, m1, hangs from a massless string and descends with an acceleration g/2. The other end is attached to a mass m2 which slides on a frictionless horizontal table. The string goes over a uniform cylinder of mass m2/2 and radius R. The cylinder rotates about a horizontal axis without friction and the string does not slip on the cylinder. Express your answers in parts b, c, and d in terms of g, m2 and R.

a) Draw free-body diagrams for the cylinder and the two masses.

b) What is the tension in the horizontal section of the string?

c) What is the tension in the vertical section of the string?

d) What is the value of the unknown mass m1?


Homework Equations





The Attempt at a Solution




part b)

T1/SUB] = m2/SUB]a
T2/SUB] -m1/SUB]g = -m1/SUB]a
T2/SUB]R - T1/SUB]R = MR2/SUP]\alpha...T2/SUB] - T1/SUB] = Ma

T1/SUB] = T2/SUB] - Ma = m1/SUB]g - .5m1/SUB]g - .25m2/SUB]g = g(.5m1/SUB] - .25m2/SUB])

part c)

T2/SUB] = T1/SUB] + Ma = .5m2/SUB]g + .25m2/SUB]g = .75m2/SUB]g

part d) it keeps canceling out,, is something wrong above
 

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?m1/SUB] = (T2/SUB] - T1/SUB])/(g/2) = (.75m2/SUB] - (g(.5m1/SUB] - .25m2/SUB]))/(g/2)
 
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