Electric field at origin due to 6 charges.

AI Thread Summary
The discussion focuses on calculating the electric field at the origin due to six charges arranged in a grid. Participants note that the x-component of the electric field may be zero due to symmetry, as there are equal positive and negative charges on either side of the y-axis. For the y-component, there is uncertainty about the calculation process, with the equation E=kq/r² mentioned as a starting point. Visualizing the charge arrangement and the corresponding electric field vectors is recommended to aid in understanding. The conversation emphasizes the importance of symmetry in simplifying the calculations.
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Problem: Charges are located in a gridline figure. The figure has these points: (-0.2m,0.3m) -2 microC, (-0.2m, 0m) +2 microC, (-0.2m,-0.3m) -2 microC, (0.2m,0.3m) +2 microC, (0.2m,0) +2 microC, and (0.2m, -0.3m) +2 microC.
a) Calculate x and y components of the electric field at the origin due to the six charges. (Try to make use of any symmetry that exists before you calculate)



Solution: I feel like the Ex component will be zero because of symmetry but am not completely sure about that because of the positive and negative charges that lie above and below the x axis. As far as the Ey component goes, I'm really unsure how to calculate it. I know to use the equation E=kq/r2 but don't really know where to start from.
 
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Draw a picture of the six charges and draw the vector of the electric field originating from each charge. Remember, the electric field of a point charge at the origin is parallel to the straight line connecting the charge with the origin, and points away from the charge if it is positive, and towards the charge when it is negative.

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