Estimate Time for Air Molecule Movement at STP

  • Thread starter Thread starter aal0315
  • Start date Start date
  • Tags Tags
    Air Molecules
AI Thread Summary
To estimate the time it takes for an air molecule to move into the region occupied by another at STP, one must calculate the average separation of nitrogen molecules, which is approximately 3.34x10^-9 meters. The root mean square speed of nitrogen molecules is calculated to be 462 m/s. By multiplying this speed by the average separation distance, the time required for one molecule to move into the space of another is found to be about 1.54 microseconds. The calculations and logic presented in the discussion are confirmed to be correct. This estimation provides insight into molecular movement dynamics in gases.
aal0315
Messages
41
Reaction score
0

Homework Statement


From the average separation between air molecules at STP, and their mean speed, estimate how long it would take one molecule to move into the region occupied by another. Assume that air consists mainly of nitrogen molecules.


Homework Equations


v(rms)=sq root(3kT/m)
molecular mass of nitrogen is 28u


The Attempt at a Solution


Do i just ignore oxygen and just work on nitrogen molecules?
I don't know how to find the average separation of air molecules at STP.
the average speed of a nitrogen molecule works out to be:
v=sq root([(3)(1.38x10^-23)(273)]/4.6x10^-26
v=462m/s
what should i do next?
 
Physics news on Phys.org
aal0315 said:
I don't know how to find the average separation of air molecules at STP.

Imagine for a moment all molecules don't move and each sits in the center of its own cube. What is volume of this cube? What is a distance to each of the neighbors?

--
methods
 
ok, so i read in my course notes that the average distance between nitrogen molecules at STP is 3.34x10^-9m because one mole of gas at STP contains 6.02x10^23 molecules and the total volume is 22.4L. So you divide the volume by the number of molecules to get the distance right? and then to get the time it takes to move, you just multiple the velocity by the distance?
so 462m/s x 3.34x10^-9 = 1.54x10^-6 seconds
does this make sense?
 
Logic looks OK to me.

--
methods
 
thank you for the help
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top