Calculating Thermodynamic Values for Different Processes

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To calculate thermodynamic values for the process from A to B in figure 2, the specific type of process is not necessary. The work can be determined by integrating or calculating the area under the AB line, which consists of a right triangle and a rectangle. The triangle's area is calculated as 1000 J, while the rectangle's area is 400 J, leading to a total work of 1400 J. Once the work is established, the other thermodynamic values such as q, ∆U, ∆H, and ∆S can be derived. This method simplifies the calculation process for the given thermodynamic scenario.
atsum
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The question is to calculate: q, w, ∆U, ∆H, ∆S for each step(A to B, B to C, C to A)

I know how to calculate the values on figure 1, but, how to calculate A to B on figure 2?

For A to B on figure 1, it is isothermal process, therefore, I can easy to find out the answer, but I don't know what is the process for A to B on figure 2.

Can anyone tell me what the condition difference (A to B) between figure 1 and 2?
 

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atsum said:
For A to B on figure 1, it is isothermal process, therefore, I can easy to find out the answer, but I don't know what is the process for A to B on figure 2.

Can anyone tell me what the condition difference (A to B) between figure 1 and 2?

Hello.

You don't need to know what kind of process is between A and B on picture 2. You simply calculate work by integrating, or simpler, by calculating surface under the AB line. It is easy to calculate, because you have one right angled triangle and one rectangle. (i will do approximation: 1atm=10^5 Pa, a 1L=1dm^3=10^-3 m^3)

Surface of triangle is:

S(t)=\frac{pV}{2}=\frac{5*10^{5}Pa*4*10^{-3}m^{3}}{2}=1000J

Surface of rectangle is:

S(r)=pV=10^{5}Pa*4*10^{-3}m=400J

So, total work is W=S(t)+S(r)=1400J

And now you can calculate everything else.
 
P.S. I have some technical issues here.. you can copy these formula code into this application, and you will see it: http://www.codecogs.com/latex/eqneditor.php
 
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