Mass, speed, and force to find new speed and distance traveled during period.

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SUMMARY

The discussion focuses on calculating the new speed and distance traveled by a train with a mass of 5.77E+6 kg, initially moving at 99.4 km/hr, after a net backward force of 1.11E+6 N is applied for 26.9 seconds. The correct approach involves using Newton's second law (f=ma) to find acceleration, followed by kinematic equations to determine the new speed and distance. The user initially misapplied the equations, confusing force and velocity, which led to incorrect results.

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  • Understanding of Newton's laws of motion
  • Familiarity with kinematic equations
  • Ability to convert units (e.g., km/hr to m/s)
  • Basic algebra for solving equations
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  • Review Newton's second law and its application in physics problems
  • Learn how to correctly apply kinematic equations in motion scenarios
  • Practice unit conversions, particularly for speed and force
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This discussion is beneficial for physics students, educators, and anyone interested in understanding motion dynamics, particularly in the context of forces acting on objects.

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. Homework Statement

A train has a mass of 5.77E+6 kg and is moving at 99.4 km/hr. The engineer applies the brakes, which results in a net backward force of 1.11E+6 N on the train. The brakes are held on for 26.9 s.

What is the new speed of the train?

How far does it travel during this period?

mass of train: 5,770,000 kg

speed of train: 99.4 km/hr (i converted it to m/s and got 27.611 m/s)

Backwards net force of: 1,110,000 N

Brakes held for: 26.9 s

2. Homework Equations

f=ma?

V=Vo+at?

X=Xo+(Vo)(t)+.5at^2?

3. The Attempt at a Solution

I am fairly new to physics and don't really know what I'm doing, anyways...first i used f=ma
and got a=.192 then i used that in the second equation and got V=1,110,005.165 N and then I plugged that into the third equation and got 29859069.4666 M but it said i was wrong :/.

I am not asking for the answer, just what equations to use and what order to do what in, of coarse if you would like to solve it for me feel free:)

-Thanks in advance!
 
Last edited by a moderator:
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Try to work with units, it helps spotting errors in your calculations.
Your 3 equations are correct, and can be used to solve the problem.

V=1,110,005.165 N
??
V in your second equation is a velocity, not a force.
 

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