Mass, speed, and force to find new speed and distance traveled during period.

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The discussion revolves around calculating the new speed and distance traveled by a train after brakes are applied. The train has a mass of 5.77 million kg and is initially moving at 99.4 km/hr, which converts to approximately 27.611 m/s. A net backward force of 1.11 million N is applied for 26.9 seconds. The participant attempts to use the equations of motion but confuses force with velocity in their calculations. The correct approach involves using the equations of motion properly, focusing on units to avoid errors.
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. Homework Statement

A train has a mass of 5.77E+6 kg and is moving at 99.4 km/hr. The engineer applies the brakes, which results in a net backward force of 1.11E+6 N on the train. The brakes are held on for 26.9 s.

What is the new speed of the train?

How far does it travel during this period?

mass of train: 5,770,000 kg

speed of train: 99.4 km/hr (i converted it to m/s and got 27.611 m/s)

Backwards net force of: 1,110,000 N

Brakes held for: 26.9 s

2. Homework Equations

f=ma?

V=Vo+at?

X=Xo+(Vo)(t)+.5at^2?

3. The Attempt at a Solution

I am fairly new to physics and don't really know what I'm doing, anyways...first i used f=ma
and got a=.192 then i used that in the second equation and got V=1,110,005.165 N and then I plugged that into the third equation and got 29859069.4666 M but it said i was wrong :/.

I am not asking for the answer, just what equations to use and what order to do what in, of coarse if you would like to solve it for me feel free:)

-Thanks in advance!
 
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Try to work with units, it helps spotting errors in your calculations.
Your 3 equations are correct, and can be used to solve the problem.

V=1,110,005.165 N
??
V in your second equation is a velocity, not a force.
 
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