Velocity of water from a hose using projectile motion experiment

AI Thread Summary
The experiment aims to determine the velocity of water from a hose using projectile motion by projecting the hose at various angles. The results for a 15-degree angle show a time of flight of 0.4 seconds and a horizontal range of 2.47 meters. Using the equation for horizontal range, the calculated velocity is approximately 6.39 m/s. This value represents the total magnitude of the water's velocity as it exits the hose. The discussion confirms the use of the cosine function to derive the horizontal component of the velocity.
Ben1
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Homework Statement


I'm doing an experiment where I'm trying to determine the velocity of a hose when fully turned on using projectile motion. I projected the hose at different angles (15,30,45,60,75,90 degrees) doing 3 tests on each 1. Here is an example I made with the a set of results -

At an angle of 15 degrees from the ground, a hose is turned on. It has a time of flight of 0.4 seconds and a horizontal range of 2.47 meters.



Homework Equations


horizontal range = v * cos θ * t



The Attempt at a Solution


Horizontal range = v * cos θ * t
2.47 = v * cos 15 * 0.4
v = 2.47 ÷ (cos 15 * 0.4) = 6.392830414 m/s

Is this the TOTAL velocity of the water coming from the hose?
 
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hi Ben, welcome to physicsforums :) yep, that's right, v is the total magnitude of the velocity of water coming from the hose. That's why you used the cos θ to get the horizontal component.
 

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