2nd year Calculus: partial derivatives

gcfve
Messages
13
Reaction score
0

Homework Statement


See attatched image.

Homework Equations


I just don't know where to start...


The Attempt at a Solution


Any help would be appreciated! :)
 

Attachments

  • cal3.jpg
    cal3.jpg
    9.2 KB · Views: 473
Physics news on Phys.org
images don't clear for a while, try writing the problem for a quicker reply

there's tips on using tex floating around or just click on other etex to see how its written
 
If u=f(x,y), where x=escos(t) and y=essin(t), show that:
second derivative of u wrt x + second derivative of u wrt y = e-2s(second derivative of u wrt s + second derivative of u wrt t)
 
Is this the question?
\frac{\partial^2u}{\partial x^2} + \frac{\partial^2u}{\partial y^2}
=~e^{-2s}(\frac{\partial^2u}{\partial s^2} + \frac{\partial^2u}{\partial t^2})

Do you know the form of the chain rule for multivariable functions? If so, start by taking the partials of u w. r. t. x and y, and then take the partials of the first with respect to x and of the second with respect to y, then add them together.
 
Ok, well I got :
\frac{\partial^2u}{\partial x^2} =-2essin(t) and

\frac{\partial^2u}{\partial y^2} = 2escos(t)
 
So what do you get for
\frac{\partial^2u}{\partial s^2}
and
\frac{\partial^2u}{\partial t^2}
 
well, from the formula,
(\frac{\partial^2u}{\partial s^2} + \frac{\partial^2u}{\partial t^2}) should = 2e3s(cos(t) - sin(t))
But I still don't understant how to get to the partails wrt s and t
I have u=f(x,y) so u=f(escost,essin t)
 
So u is a function of x and y, and x and y are each functions of s and t. Here's the form of the chain rule for one of the partials you need.

\frac{\partial u}{\partial s}~=~\frac{\partial u}{\partial x}\frac{\partial x}{\partial s} + \frac{\partial u}{\partial y}\frac{\partial y}{\partial s}

The other partial derivative is very similar, but any partial with respect to s should be with respect to t.
 
Ok, well when I tried to do that I got answerd without sin and cos in them.. is what i did so far right?
and is there a formula for finding the second partials wrt s and t?
 
Back
Top