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#3
gcfve
13
0
If u=f(x,y), where x=escos(t) and y=essin(t), show that:
second derivative of u wrt x + second derivative of u wrt y = e-2s(second derivative of u wrt s + second derivative of u wrt t)
Is this the question?
\frac{\partial^2u}{\partial x^2} + \frac{\partial^2u}{\partial y^2}
=~e^{-2s}(\frac{\partial^2u}{\partial s^2} + \frac{\partial^2u}{\partial t^2})
Do you know the form of the chain rule for multivariable functions? If so, start by taking the partials of u w. r. t. x and y, and then take the partials of the first with respect to x and of the second with respect to y, then add them together.
#5
gcfve
13
0
Ok, well I got :
\frac{\partial^2u}{\partial x^2} =-2essin(t) and
So what do you get for
\frac{\partial^2u}{\partial s^2}
and
\frac{\partial^2u}{\partial t^2}
#7
gcfve
13
0
well, from the formula,
(\frac{\partial^2u}{\partial s^2} + \frac{\partial^2u}{\partial t^2}) should = 2e3s(cos(t) - sin(t))
But I still don't understant how to get to the partails wrt s and t
I have u=f(x,y) so u=f(escost,essin t)
The other partial derivative is very similar, but any partial with respect to s should be with respect to t.
#9
gcfve
13
0
Ok, well when I tried to do that I got answerd without sin and cos in them.. is what i did so far right?
and is there a formula for finding the second partials wrt s and t?