Magnitude of bullet fired into gel

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    Bullet Magnitude
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The discussion revolves around calculating the magnitude of the bullet's deceleration after being fired into a dense material. The bullet, with an initial speed of 330 m/s, comes to a stop after traveling 25.0 cm. The relevant equation of motion, v^2 = u^2 + 2as, is suggested to find the acceleration, where the final speed is 0 m/s. The expected outcome is a negative value for acceleration, indicating it opposes the bullet's initial direction. Understanding this concept is crucial for solving the problem accurately.
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Homework Statement


A rifle bullet with a muzzle speed of 330 m/s is fired directly into a special dense material that stops the bullet in 25.0 cm. Assuming the bullet's deceleration to be constant, what is its magnitude?

x=25.0cm
V=330 m/s

Homework Equations



?

The Attempt at a Solution



I don't fully understand the problem, to me it sounds like they want the magnitude of force exerted on the bullet in the opposite direction it was fired? I'm really confused.

Thanks
 
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No, they are looking for the magnitude of the bullet's acceleration (deceleration).
 
The initial speed, u, is 330m/s, the final speed, v is 0 m/s since the bullet comes to rest. The bullet travels a distance, s of 0.25m.

The equation of motion v^2=u^2 +2as should be of help.

Note that this will give you a negative acceleration which is to be expected as it is opposing the direction of motion.
 

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