Young's Modulus of Pressure Sensor

AI Thread Summary
To determine Young's Modulus of Elasticity (E) for the elastic block in the pressure sensor setup, the strain is calculated using the gauge factor and the change in resistance, resulting in a strain of 4 x 10^-5. The next step involves calculating stress, which requires the area of the top surface where pressure is applied. The pressure of 1 mm Hg needs to be converted into a stress value, typically in Pascals, using the formula for stress (Pressure = Force/Area). The challenge lies in obtaining the area to finalize the calculation of Young's Modulus. Understanding the relationship between pressure, force, and area is crucial for solving this problem.
ptar
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Homework Statement


Here's the question, verbatim;
We want to build a pressure using a block of elastic material, where the pressure applied to the top surface is measured by a strain gauge mounted on one of the side walls of the block. The gauge factor of the strain gauge is 2.5. When 1 mm Hg of pressure is applied to the top surface, we obtain a delta R/R of 0.01% on the strain gauge. The nominal resistance of the strain gauge is 1000 Ohm.
(a) What is Young's Modulus of Elasticity (E) for the elastic block?


Homework Equations


Young's Modulus= Stress/ Strain = (F/A) / (delta l/l)


The Attempt at a Solution


Here the strain can also be given by the formula ((1/F) x delt.R/R), where F is the gauge factor. Plugging numbers in here, I've worked out the strain to be 4 x 10^-5. However, I have no idea what to do next. I'm sure you need area to work out stress. Or would integrating the pressure work, as pressure is dF/dA? But then you would still be left with a variable in the stress result.

Please help! Thanks.
 
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I have this same problem for my assignment and am stuck. I've found out the strain but no idea on working out the stress.
ptar said:

Homework Statement


Here's the question, verbatim;
We want to build a pressure using a block of elastic material, where the pressure applied to the top surface is measured by a strain gauge mounted on one of the side walls of the block. The gauge factor of the strain gauge is 2.5. When 1 mm Hg of pressure is applied to the top surface, we obtain a delta R/R of 0.01% on the strain gauge. The nominal resistance of the strain gauge is 1000 Ohm.
(a) What is Young's Modulus of Elasticity (E) for the elastic block?


Homework Equations


Young's Modulus= Stress/ Strain = (F/A) / (delta l/l)


The Attempt at a Solution


Here the strain can also be given by the formula ((1/F) x delt.R/R), where F is the gauge factor. Plugging numbers in here, I've worked out the strain to be 4 x 10^-5. However, I have no idea what to do next. I'm sure you need area to work out stress. Or would integrating the pressure work, as pressure is dF/dA? But then you would still be left with a variable in the stress result.

Please help! Thanks.
 
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