What is the Velocity and Direction of a Puck on an Air Hockey Table?

AI Thread Summary
To determine the velocity and direction of a puck on an air hockey table, the initial velocity and acceleration components are given: v0x = +5.6 m/s, ax = +6.3 m/s², v0y = +9.8 m/s, and ay = -3.6 m/s². The correct approach involves calculating the final velocities for both the x and y components using the equation v = u + at. After obtaining the final velocities, vector addition will yield the resultant velocity, from which the magnitude and direction relative to the +x axis can be derived. Properly applying these calculations will provide the required answers for the puck's motion.
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Homework Statement


A puck is moving on an air hockey table. Relative to an x, y coordinate system at time t = 0 s, the x components of the puck's initial velocity and acceleration are v0x = +5.6 m/s and ax = +6.3 m/s2. The y components of the puck's initial velocity and acceleration are v0y = +9.8 m/s and ay = -3.6 m/s2. Find (a) the magnitude v and (b) the direction θ of the puck's velocity at a time of t = 0.50 s. Specify the direction relative to the +x axis.


Homework Equations


v= u +at
v^2 = U^2 + 2as
s = ut +1/2at^2
s = vt +1/2at^2


The Attempt at a Solution



i don't know how to approach this, in fact i don't even know if I am using the right equations. since there are X and Y component. it would be incorrect for me to find V by only using X or V ... please help.
 
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If you solve the final velocities for each individual component of the puck's movement you will get two vectors. Using vector additions you can get a resultant….from there you should be able to find the angle relative to the x-axis.
 
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