Calculating Young's Modulus of Elasticity for 0.1% Carbon Steel

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The discussion focuses on calculating Young's modulus of elasticity for 0.1% carbon steel using tensile test results. The user calculates a modulus of 14.32 x 10^9 Pa, significantly lower than the typical value of 207 x 10^9 Pa. Participants suggest verifying the unit of area and ensuring the force is correctly measured in Newtons, not kilonewtons. Despite these checks, the calculated value remains far from the expected range, indicating a potential error in the process. The conversation highlights the importance of accurate unit conversions and calculations in material property assessments.
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I am trying to calculate youngs modulus of elasticity for results from a tensile test but can't seem to get a figure close to that of the common figure for the material

Material 0.1% carbon steel
Area = 20 x 10-6
Yield force = 6009N
Length increase at yield force = 0.537mm = 0.000537m
Original length = 25.6mm = 0.0256mE = σ/ε

E = (6006/20x10-6) / (0.000537/0.0256)
E = 14.32 x 109
Typical value = 207 x 109

Iv obviously went very wrong somewhere but i don't know where

Thanks
 
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Your calculations seem fine, what is the unit of the area? You can also make sure that the force is in N, not in kN or something.
 
The unit of area is m^2, and the force was 6.009 KN so 6009 N. Its way off the typical value though, it doesn't make sense?
 
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