A car placed on incline and a mass placed on the car

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Homework Help Overview

The problem involves a car of mass M sliding down a frictionless incline with an additional mass m placed on it. The task is to determine the kinetic coefficient of friction between the two masses, given that m moves parallel to the incline when the system is released.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to analyze the forces acting on both masses and has established a coordinate system. They express that the masses must share the same acceleration but have not reached a solution.
  • Some participants inquire about the downslope acceleration of the system and suggest that both masses must be moving together, prompting the original poster to clarify their calculations.

Discussion Status

The discussion is ongoing, with participants exploring the relationship between the masses and their accelerations. Some guidance has been offered regarding the need to calculate the downslope acceleration, but no consensus or resolution has been reached yet.

Contextual Notes

The original poster indicates they are new to the forum and may be unfamiliar with the posting format, which could affect the clarity of their contributions.

eren.kizildag
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Homework Statement


The car of mass M is sliding on the incline. A mass of m is placed as shown. There is friction between m and M in the vertical surface of M . The incline is frictionless. System is released, and it is observed that m moves parallel to the incline. We are asked to find the kinetic coefficient of friction. (Angle is theta)


Homework Equations


Ff+masin(theta)=mg, N=macos(theta), Ff=Mk*N where Mk is the kinetic coefficient of friction. N is the reaction force between M and m.


The Attempt at a Solution


I have chosen the ordinary coordinate system. The masses must have same acceleration. (In both x and y direction). I also showed the friction force acting on m. And I wrote down reaction forces, but could not get the correct answer.

(I'm sorry, I am new at the forum, and I don't know how to use the forum properly. If I made a mistake about the body of the message, please forgive me.)
 

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Hello eren.kizildag. Welcome to Physics Forums.

Since m is not sliding on M, both M and m must be moving downslope together. Have you worked out the downslope acceleration of the pair as a function of g and θ ?
 
Yeah, but I got nothing.
 
eren.kizildag said:
Yeah, but I got nothing.

No acceleration downslope? Perhaps you could show your calculation?
 

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