A car placed on incline and a mass placed on the car

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A car of mass M is sliding down a frictionless incline with an angle theta, while a mass m is placed on it, experiencing friction between them. The system is released, and m moves parallel to the incline, prompting the need to determine the kinetic coefficient of friction. The discussion highlights the importance of both masses having the same acceleration in the x and y directions. Participants emphasize the necessity of calculating the downslope acceleration of the combined system to solve for the friction coefficient. The conversation reflects a collaborative effort to clarify the mechanics involved in the problem.
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Homework Statement


The car of mass M is sliding on the incline. A mass of m is placed as shown. There is friction between m and M in the vertical surface of M . The incline is frictionless. System is released, and it is observed that m moves parallel to the incline. We are asked to find the kinetic coefficient of friction. (Angle is theta)


Homework Equations


Ff+masin(theta)=mg, N=macos(theta), Ff=Mk*N where Mk is the kinetic coefficient of friction. N is the reaction force between M and m.


The Attempt at a Solution


I have chosen the ordinary coordinate system. The masses must have same acceleration. (In both x and y direction). I also showed the friction force acting on m. And I wrote down reaction forces, but could not get the correct answer.

(I'm sorry, I am new at the forum, and I don't know how to use the forum properly. If I made a mistake about the body of the message, please forgive me.)
 

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Hello eren.kizildag. Welcome to Physics Forums.

Since m is not sliding on M, both M and m must be moving downslope together. Have you worked out the downslope acceleration of the pair as a function of g and θ ?
 
Yeah, but I got nothing.
 
eren.kizildag said:
Yeah, but I got nothing.

No acceleration downslope? Perhaps you could show your calculation?
 

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