A little help with electric potential.

AI Thread Summary
To solve the electric potential problem, it's essential to consider the electric field in three distinct regions based on the configuration of charges. The potential is calculated using the integral of E dot dS, which simplifies to (kq/r) evaluated from the point of interest to infinity. The electric field varies in the regions: from 1.4 to 4.2, it is influenced only by the inner sphere; from 4.2 to 7, it includes contributions from both the inner sphere and the inner surface of the shell; and beyond 7, it accounts for all charges. The initial calculation of 2.15059 V is incorrect because it did not incorporate these varying electric fields across the specified regions. Understanding these distinctions is crucial for arriving at the correct potential value.
JamesL
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Here is the problem:

http://uploads.offtopic.com/files/physprob15.bmp

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The way we were taught in class so far to find the potential was using the integral of E dot dS. Which works itself down to (kq/r) evaluated from the r you are looking for to infinity.

In which case, V would equal 2.15059 v. But this answer is incorrect according to my homework service.

Any ideas?
 
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You should have three different expressions for the electric field for the three regions. Did you account for that in your integration to infinity?
 
Tide said:
You should have three different expressions for the electric field for the three regions. Did you account for that in your integration to infinity?

no, i don't think so. could you explain more?
 
In the region 1.4 < r < 4.2 the electric field is determind only by the charge on the inner sphere. In 4.2 < r < 7 the electric field is determined by both the charge on the inner sphere AND the inner surface of the shell. And outside the configuration r > 7 the electric field is due to the charge on the inner sphere and both the inner and outer surfaces of the shell.
 
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