A Question about Kirchoff's Voltage Law

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Kirchoff's Voltage Law dictates that the sum of voltage rises and drops in a closed loop must equal zero. In the discussed example, the loop's clockwise direction determines the signs of the voltages, with E1 considered a voltage rise and E2 a voltage drop. This is due to the current flowing into E1's negative side and E2's positive side. Properly assigning signs based on the chosen loop direction is crucial for accurate analysis. Understanding these principles is essential for applying Kirchoff's Law effectively in circuit analysis.
bibo_dvd
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Hello Guys

My Question about Kirchoff's Law is : why in this Example
we considered that E2 is a Voltage Drop not a Voltage Rise ??

i mean why we didn't say that : +E2-V1-V2+E2=0 ?


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and Thanks Guys :)) !
 
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It's because the loop has a direction. In this case, the loop is clockwise, making E1 positive but E2 negative.
 
Pick a direction for your analysis. Assign a sign to all the voltage rises, and the opposite sign to the voltage drops. The sum of all the voltage rises =the sum of all the voltage drops around the circuit.

In your example, the current loop is clock wise, so the current flows into the negative side of E1 (voltage rise), and into the positive side of E2 (voltage drop).
 

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