How Does a Double-Pulley Modified Atwood Machine Work?

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The discussion focuses on the mechanics of a double-pulley modified Atwood machine, emphasizing the assumptions of no friction and negligible mass for the pulleys and string. It outlines a three-stage analysis of the forces acting on two masses, m1 and m2, with m1 attached to a smaller pulley. The total forces acting on both masses are zero, indicating equilibrium in the system. The tension in the string is uniform, leading to the conclusion that the forces on m1 consist of two tension forces upward against its weight, while m2 experiences one tension force upward against its weight. This analysis highlights the balance of forces and the role of tension in the system's dynamics.
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1. For the modified Atwood machine of this problem, assume that the two masses do move. Also assume that there is no friction, and that gravity is the only force acting. Also assume that you can ignore the mass of the pulleys and of the connecting rod and string. Notice that mass m1 is rigidly attached to the smaller pulley.
Do this problem in 3 stages, by answering the following questions.

1. The total force acting on mass m1 and that acting on mass m2 areboth zero TF
2. in the same direction TF
3. equal in magnitude TFhttp://b.imagehost.org/0304/lerner3_53.gif [/URL]






3. my guess is that since the tension force is the same everywhere on this massless string, then the total force acting on mass m1 and m2 should be both zero... but its known whether the pulleys are in motion or not so...
 
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Look 2 chords are pulling up on the mass m1 and only one on the mass m2

So for mass m1 it becomes 2T up and m1g down and for other T up and m2g down
 
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