A Solid Sphere Release From Rest at the top of a Ramp.

Thread starter aZenki
Start date Nov 13, 2006
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Ramp Release Rest Solid Solid sphere Sphere

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A 2.0 kg solid sphere is released from rest at the top of a 0.75m high ramp and rolls without slipping down a 5.3m long incline. The total kinetic energy (Ktotal) is calculated using the formula Ktotal = mgh, which accounts for gravitational potential energy. The kinetic energy is divided into rotational (Krot) and translational (Ktranslation) components, with their ratio determined by the moment of inertia, specifically Krot/Ktranslation = 2/5. The translational kinetic energy is derived as Ktranslation = 5/7 mgh, reflecting the energy conservation principle. The work done by friction is considered zero, confirming that pure rolling occurs.

Nov 13, 2006

aZenki

Please help me with this question. Thank you.

A 2.0 kg solid sphere (radius = 0.10m) is released from rest at the top of a ramp and allow to roll without slipping. The ramp is 0.75m high and 5.3 m long. Find Ktotal, Krot, and Ktranslation.

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Nov 13, 2006

Vagrant

Pure rolling takes place, work done by friction is 0. Energy is conserved. Ktotal=mgh, Krot/Ktranslation=2/5 ie in ratio of moment of inertia. Ktranslation=5/7 mgh etc

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