A +'ve charge Q is fixed to the origin. A -'ve charge 9Q

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Homework Help Overview

The problem involves two fixed charges: a positive charge Q at the origin and a negative charge with magnitude 9Q located a distance d along the positive x-axis. The objective is to determine the position of a small positive test charge q where it experiences zero net electrical force from these two charges.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to consider the net force on the test charge, questioning how to account for three charges in the force equations. There is an exploration of the roles of repulsive and attractive forces acting on the test charge.

Discussion Status

The discussion is ongoing, with participants attempting to clarify the relationship between the forces acting on the test charge and how to set up the equations correctly. Some guidance has been provided regarding the use of vector addition and the importance of relative charge magnitudes.

Contextual Notes

Participants note the absence of specific numerical values for the charges and distances, which raises questions about how to apply vector addition in this context.

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Homework Statement



A positive charge Q is fixed to the origin. A negative charge with magnitude 9Q is fixed along the positive x-axis a distance d to the right of the origin. Determine a point where a small positive test charge q will experience zero electrical force from the two charges, or show that there is no such point. Draw diagrams to help you.

Homework Equations


[/B]
FE = kq1q2 / r2

The Attempt at a Solution



(+Q)--------d---------(-9Q)

I know the test charge must be to the left of the positive charge Q, and I tried to solve by rearranging the equation to solve to r, but that leaves you with dividing the force, which in this case is zero which does not work.

r = √kq1q2 / FE
But FE = 0 so this does not work.
 
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Your equation is for the force between two charges. There are three in the problem. The net force must sum to zero not the two individual forces.
 
CWatters said:
Your equation is for the force between two charges. There are three in the problem. The net force must sum to zero not the two individual forces.
So would the equation for three charges just include a q3 at the end? Thus making the small positive test charge 8Q to have it equal zero?
 
abm77 said:
So would the equation for three charges just include a q3 at the end?

Not sure I follow that.

The test charge q is +ve so there are two forces on it..

1) A repulsive force between +Q an +q
2) An attractive force between -9Q and +q

The question asks where must +q be for these two forces sum to zero. Have you studied vector addition?
 
CWatters said:
Not sure I follow that.

The test charge q is +ve so there are two forces on it..

1) A repulsive force between +Q an +q
2) An attractive force between -9Q and +q

The question asks where must +q be for these two forces sum to zero. Have you studied vector addition?

How would vector addition work for this question as there are no values for the variables?
 
abm77 said:
How would vector addition work for this question as there are no values for the variables?
The values are irrelevant, only the relative size of the charges is important (and you know that one has 9 times more charge than the other).

Place the test charge at an arbitrary position on the x-axis, then write an equation for F1 the force on the test charge from the one charge and another equation for F2 the force on the test charge from the other charge. The net force is F1+F2. The problem asks you to find where this net force is zero.
 
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