Engineering AC circuit: Find the current through the inductor & capacitor

Click For Summary
The discussion focuses on calculating the current through an inductor and capacitor in an AC circuit. The user seeks confirmation of their results, specifically I(L) and I(C), which are linked to I2 and I3. Another participant validates the calculations but points out an error in evaluating I1, providing the correct value as 3.4955 ∠ -11.2195°. The mistake in I1 does not impact the results for I(L) and I(C). The conversation emphasizes the importance of accurate calculations in circuit analysis.
Michael_0039
Messages
59
Reaction score
7
Homework Statement
AC circuit: Find the current through the inductor & capacitor
Relevant Equations
nil
Hi!

I wonder if it is correct. Can someone confirm (maybe with a software) ?

New Doc 2019-11-10 17.34.03_3.jpg


New Doc 2019-11-10 17.34.03_1.jpg


New Doc 2019-11-10 17.34.03_2.jpg


I(L) = I2
I(C) = I2 - I3
--

Thanks.
 
Physics news on Phys.org
Your work looks good. I worked the problem via nodal analysis and obtained the same results. Good job.
 
  • Like
Likes phinds and Michael_0039
Michael_0039, at the very end of your work, you didn't evaluate the expression for I1 correctly.

The correct value for I1 is 3.4955 ∠ -11.2195°

This doesn't affect your result for I(L) and I(C), but it is still a mistake.
 
The Electrician said:
Michael_0039, at the very end of your work, you didn't evaluate the expression for I1 correctly.

The correct value for I1 is 3.4955 ∠ -11.2195°

This doesn't affect your result for I(L) and I(C), but it is still a mistake.
You are right, I forgot (10+(10*I2))/12
 
Thread 'Full bridge circuit with inductor and resistor'
The above is the circuit i am calculating the inductor current. During the positive half of the sine input D1 and D3 are conducting so the circuit becomes My calculations are as below Are the above equations ok? When transitioning from +Ve cycle to -Ve sine wave does the above equations still applicable? During the negative cycle the diodes D2 and D4 are conducting and the current direction is going into the inductor same as when diodes D1 and D3 are conducting. According to me the same...

Similar threads

Replies
5
Views
2K
Replies
1
Views
1K
Replies
4
Views
1K
Replies
26
Views
3K
Replies
2
Views
1K
Replies
3
Views
2K
Replies
4
Views
2K