Engineering AC Source driving an RLC circuit....

Click For Summary
The discussion revolves around calculating the current and voltage across a capacitor in an RLC circuit driven by an AC source. The circuit consists of a 10V, 100Hz input with a 1Ω resistor, 1Ω inductive reactance, and 1Ω capacitive reactance in series. The correct calculation for the total impedance (Z) is 1Ω, leading to a current (I) of 10A. The voltage across the capacitor (Vc) was initially miscalculated but was corrected to -10j volts after considering the complex nature of reactance. The final consensus confirms the calculations for both current and voltage across the capacitor as accurate.
jojo13
Messages
20
Reaction score
1

Homework Statement



10 v, 100 hz goes into a circuit of a 1o resistor, a 1o inductive reactance and a 1o capacitive reactance that are in series.

What is the current. What is the V across the cap.

Homework Equations

and the attempt at a solution[/B]

So I know I = V/Z and Z = sqrt( R^2 + (XL^2 - XC^2 )

And the question gives us the inductive reactance and capacitive reactance which is XL = 1 and XC = 1, and it gives us R = 1

So now, Z = sqrt(1^2 + (1^2 - 1^2 ) ) = 1

And I = V/Z = 10/1 = 10 A

Is that correct for the current of the circuit? If so, how do I calculate the voltage across the capacitor?

Is it voltage of capacitor, Vc = I * XC = 10 * 1 = 10 V ? Is that correct?
 
Last edited:
Physics news on Phys.org
Yes, that is the correct value of the current.

and the voltage across the capacitor is almost correct.

Revisit your XL and XC. Isn't there a "j" in the reactance?
 
magoo said:
Yes, that is the correct value of the current.

and the voltage across the capacitor is almost correct.

Revisit your XL and XC. Isn't there a "j" in the reactance?

Ah, would it be, Vc = I * Zc = 10 * (1/j) = 10/j = -10j
 
Now it is correct. Nice work!
 
  • Like
Likes jojo13
magoo said:
Now it is correct. Nice work!

Thanks
 
Last edited:
Yes, you've got it right.
 
  • Like
Likes jojo13
Greetings to all, I am writing with a question regarding graph generation in LTSpice. I am using LTSpice XVII and am trying to plot AM-AM and AM-PM characterization for a power amplifier, but I haven't been successful yet, likely due to my lack of practice with this specific analysis. I have been using a square wave input at 8.2 MHz as the voltage waveform for my power amplifier. It is said that for a switching amplifier like Class-D, the AM-AM / AM-PM (amplitude-to-amplitude and...
Thread 'How do I determine the resistance for RLC low pass filter?'
Hi, I am trying to build a RLC low pass filter that atenuates the frequency below 4500 Hz. However, I have encountered some problem when choosing the correct R to work with. Here is the Circuit Here is the original sound. Here is my code in Matlab function Vout = myFilterCircuit(Vin,h) n_V = length(Vin); f_7 = 4470;; % Undesired frequency h_7 = h; % delta time % These are for the constant and initialization of the variables t_7 = 0:h_7:(n_V-1)*h_7; % This is the independent variable...

Similar threads

Replies
5
Views
3K
Replies
17
Views
2K
Replies
1
Views
2K
Replies
8
Views
3K
Replies
3
Views
1K
Replies
32
Views
2K
Replies
26
Views
3K