Accel. of eletron in Electric field.

AI Thread Summary
To determine the electric field required to accelerate electrons in a TV tube from rest to one-tenth the speed of light over a distance of 5.5 cm, the uniform acceleration formula v^2 = V_o + 2a(delta X) is applied. The calculated acceleration was initially found to be 2.72 m/s², but after re-evaluation, it was corrected to 8.18e15 m/s². The relationship a = q/m(E) was used to derive the electric field E, but the initial attempts yielded incorrect values. The discussion emphasizes the need for accurate calculations and proper rearrangement of formulas to find the correct electric field strength. Continued recalculations are necessary to achieve the correct result.
Lance WIlliam
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Homework Statement



How strong an electric field is needed to accelerate electrons in a TV tube from rest to one-tenth the speed of light in a distance of 5.5

Homework Equations



I used uniform accel. forumla v^2=V_o_+2a(delta X)
v=3e7 (1/10th speed of light)
V_o_=Rest
m=9.11e-31(mass of eletron)
delta X= .055meters
all to find (a)
to find the Accelaration

and a=q/m(E)


The Attempt at a Solution



I need to find E i believe I came up with
a=2.72 m/s^2
and E= 3.98e-41 which was wrong...;/

Thankyou
 
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Lance WIlliam said:
I need to find E i believe I came up with
a=2.72 m/s^2
Redo that calculation. (Your equation is OK.)
 
Ok I did it again and got 8.18e15 for my (a)
Then I need to find (E) so I changed the formula around so its "a/(q/m)=E" and I got 1.19e-33 ...wrong again...
 
Lance WIlliam said:
Ok I did it again and got 8.18e15 for my (a)
Looks good.
Then I need to find (E) so I changed the formula around so its "a/(q/m)=E" and I got 1.19e-33 ...wrong again...
That formula, though oddly written (get that fraction out of the denominator), is perfectly OK. Redo the calculation.
 
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