Accelerate Protons to 5.0x10^6 m/s: Voltage & Kinetic Energy Calculations

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To accelerate protons from rest to a speed of 5.0x10^6 m/s, the required voltage can be calculated using the equation qV = (mv^2)/2, where q is the charge of the proton, m is its mass, and v is the final speed. The kinetic energy of the protons at this speed can be determined using the formula K = 0.5mv^2, yielding results in joules. To convert the kinetic energy from joules to electronvolts (eV), divide by 1.67x10^-19. This approach provides a systematic method for solving the problem of voltage and kinetic energy for accelerated protons. Understanding these calculations is essential for applications in particle physics and accelerators.
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I'm trying to figure out this problem and i am having no luck. Any help would be great.

a) How much voltage would be need, in order to accelerate protons from rest to 5.0x10 to the 6th m/s.
b) what is the kinetic energy of these protons in eV, after they hit the top speed indicated in part a?
 
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The amount of work done by the electric field is E = q V.
 
try this

Try this,
qV=(m*v^2)/2
q= charge on proton, v= speed, m= mass

Kinetic energy, K= 0.5m*v^2 units will be in joules.
to convert it in eV divide it by 1.67*10^-19.
have better luck this time
 

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